Simple and Compound Interest for SSC GD, Download Free PDF

Preparing for the SSC GD Constable exam? You are probably dreaming of wearing the uniform of the BSF, CRPF, or CISF. To make that dream true, you need to clear the written exam first. In the Elementary Mathematics section, there is one topic that confuses many students: Simple Interest (SI) and Compound Interest (CI). Do you get scared seeing words like “Principal,” “Amount,” or “Compounded Annually”? Do you feel calculating interest takes too much time? Don’t worry, questions in SSC GD are not complicated. They are direct and formula-based. The examiner just wants to check if you know basic formulas. If you memorize just 2-3 small formulas, you can easily score 2 to 3 marks in this section. In this blog, we have provided a free exam-level questions PDF of Simple and Compound Interest for SSC GD

Why is Simple & Compound Interest Important?

In the SSC GD Math section (20 questions), this topic is a “Must-Do.”

• Fixed Weightage: You will definitely find 1 question on Simple Interest and 1 or 2 on Compound Interest.
• Easy Calculation: The numbers in SSC GD are usually easy to cut (like 10%, 20%, ₹1000). You won’t need a calculator.
• Formula Based: Unlike Profit & Loss where language can be tricky, Interest questions are straightforward. Put values in the formula, get the answer.

Understanding the Difference (In Simple Words)

Before you solve, you must know the difference.

• Simple Interest (SI): This is like a flat fee. If you borrow money, you pay the same extra amount every year.
  • Formula: SI = (P x R x T) / 100
• Compound Interest (CI): This is “Interest on Interest.” The money grows faster here because you pay interest on the previous year’s interest as well.
  • Formula: Amount = P(1 + R/100)^T

Download Free PDF of SI & CI Questions for SSC GD

We have prepared a comprehensive PDF containing exam-level questions. We have chosen questions that match the exact difficulty level of the SSC GD exam. Download it, save it on your phone, and practice whenever you get time.

Q1. Find the Simple Interest on ₹8000 at 5% per annum for 4 years.

(a) ₹1200
(b) ₹1500
(c) ₹1600
(d) ₹1800

Answer: (c) ₹1600

Logic:
SI = (8000 × 5 × 4) / 100
= ₹1600

Q2. A sum of money becomes double in 8 years at Simple Interest. What is the rate per annum?

(a) 10%
(b) 12.5%
(c) 15%
(d) 20%

Answer: (b) 12.5%

Logic:
To double, Interest = Principal
100 = (100 × R × 8) / 100
8R = 100
R = 12.5%

Q3. Find the Compound Interest on ₹1000 for 2 years at 10% per annum.

(a) ₹200
(b) ₹210
(c) ₹220
(d) ₹190

Answer: (b) ₹210

Logic:
10% of 1000 = 100 (1st year)
Amount after 1st year = 1100
10% of 1100 = 110 (2nd year)
Total CI = 100 + 110 = ₹210

Q4. The difference between CI and SI for 2 years on a certain sum at 5% per annum is ₹25. Find the sum.

(a) ₹10,000
(b) ₹8,000
(c) ₹12,000
(d) ₹15,000

Answer: (a) ₹10,000

Logic:
Difference for 2 years:
Diff = P(R/100)²
25 = P(5/100)²
25 = P(1/400)
P = ₹10,000

Q5. In how much time will ₹5000 amount to ₹6000 at 10% per annum Simple Interest?

(a) 1 year
(b) 2 years
(c) 3 years
(d) 4 years

Answer: (b) 2 years

Logic:
Interest = 6000 − 5000 = 1000
1000 = (5000 × 10 × T) / 100
1000 = 500T
T = 2 years

Q6. If a sum of money amounts to ₹1331 in 3 years at 10% Compound Interest, what is the Principal?

(a) ₹1000
(b) ₹1100
(c) ₹900
(d) ₹1200

Answer: (a) ₹1000

Logic:
10% means 10 becomes 11
In 3 years: 10³ becomes 11³
11³ = 1331
Principal = 10³ = ₹1000

Q7. At what rate percent per annum will ₹2000 amount to ₹2420 in 2 years at Compound Interest?

(a) 5%
(b) 10%
(c) 8%
(d) 12%

Answer: (b) 10%

Logic:
√(2420 / 2000) = √(121 / 100) = 11 / 10
Money grows from 10 to 11
Rate = 10%

Q8. Simple Interest on a sum for 3 years at 10% is ₹300. Find the Compound Interest on the same sum for 2 years at the same rate.

(a) ₹200
(b) ₹210
(c) ₹220
(d) ₹205

Answer: (b) ₹210

Logic:
SI per year = 300 / 3 = 100
Principal = 100 × 100 / 10 = 1000
CI for 2 years = 100 + 100 + Interest on 100
= 210

Q9. A sum becomes 3 times itself in 5 years at Simple Interest. In how many years will it become 9 times?

(a) 15 years
(b) 20 years
(c) 12 years
(d) 10 years

Answer: (b) 20 years

Logic:
To become 3 times → Interest = 2P in 5 years
To become 9 times → Interest = 8P
8P is 4 times of 2P
Time = 5 × 4 = 20 years

Q10. What is the amount if interest is compounded half-yearly on ₹10,000 for 1 year at 20% per annum?

(a) ₹12,000
(b) ₹12,100
(c) ₹11,000
(d) ₹12,500

Answer: (b) ₹12,100

Logic:
Half-yearly compounding:
Rate = 10%, Time = 2 half-years
1st half-year interest = 1000
2nd half-year interest = 1100
Amount = 10000 + 1000 + 1100 = ₹12,100

How to Prepare Interest Questions Easily?

Here are some tips and tricks that will help you solve simple and compound interest questions easily.

• Master the Difference Trick: The question “Difference between SI and CI for 2 years” is the most repeated in SSC GD. Memorize the formula D = P(R/100)². It solves the question in 10 seconds.
• Use the Ratio Method for Compound Interest; don’t use the long formula. Use ratios.
  • 2 Years = 2:1
  • 3 Years = 3:3:1
  • This makes the calculation much faster.
• Understand Half-Yearly: If the question says “Compounded Half-Yearly,” just do two things: Rate becomes Half and Time becomes Double. That’s it.
• Practice with Topic Tests: Reading formulas is not enough. You need to solve. Attempt our Free Topic Tests to check your calculation speed.

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