Simple and Compound Interest for SSC GD, Download Free PDF
Preparing for the SSC GD Constable exam? You are probably dreaming of wearing the uniform of the BSF, CRPF, or CISF. To make that dream true, you need to clear the written exam first. In the Elementary Mathematics section, there is one topic that confuses many students: Simple Interest (SI) and Compound Interest (CI). Do you get scared seeing words like “Principal,” “Amount,” or “Compounded Annually”? Do you feel calculating interest takes too much time? Don’t worry, questions in SSC GD are not complicated. They are direct and formula-based. The examiner just wants to check if you know basic formulas. If you memorize just 2-3 small formulas, you can easily score 2 to 3 marks in this section. In this blog, we have provided a free exam-level questions PDF of Simple and Compound Interest for SSC GD
In the SSC GD Math section (20 questions), this topic is a “Must-Do.”
Before you solve, you must know the difference.
We have prepared a comprehensive PDF containing exam-level questions. We have chosen questions that match the exact difficulty level of the SSC GD exam. Download it, save it on your phone, and practice whenever you get time.
Q1. Find the Simple Interest on ₹8000 at 5% per annum for 4 years.
(a) ₹1200
(b) ₹1500
(c) ₹1600
(d) ₹1800
Answer: (c) ₹1600
Logic:
SI = (8000 × 5 × 4) / 100
= ₹1600
Q2. A sum of money becomes double in 8 years at Simple Interest. What is the rate per annum?
(a) 10%
(b) 12.5%
(c) 15%
(d) 20%
Answer: (b) 12.5%
Logic:
To double, Interest = Principal
100 = (100 × R × 8) / 100
8R = 100
R = 12.5%
Q3. Find the Compound Interest on ₹1000 for 2 years at 10% per annum.
(a) ₹200
(b) ₹210
(c) ₹220
(d) ₹190
Answer: (b) ₹210
Logic:
10% of 1000 = 100 (1st year)
Amount after 1st year = 1100
10% of 1100 = 110 (2nd year)
Total CI = 100 + 110 = ₹210
Q4. The difference between CI and SI for 2 years on a certain sum at 5% per annum is ₹25. Find the sum.
(a) ₹10,000
(b) ₹8,000
(c) ₹12,000
(d) ₹15,000
Answer: (a) ₹10,000
Logic:
Difference for 2 years:
Diff = P(R/100)²
25 = P(5/100)²
25 = P(1/400)
P = ₹10,000
Q5. In how much time will ₹5000 amount to ₹6000 at 10% per annum Simple Interest?
(a) 1 year
(b) 2 years
(c) 3 years
(d) 4 years
Answer: (b) 2 years
Logic:
Interest = 6000 − 5000 = 1000
1000 = (5000 × 10 × T) / 100
1000 = 500T
T = 2 years
Q6. If a sum of money amounts to ₹1331 in 3 years at 10% Compound Interest, what is the Principal?
(a) ₹1000
(b) ₹1100
(c) ₹900
(d) ₹1200
Answer: (a) ₹1000
Logic:
10% means 10 becomes 11
In 3 years: 10³ becomes 11³
11³ = 1331
Principal = 10³ = ₹1000
Q7. At what rate percent per annum will ₹2000 amount to ₹2420 in 2 years at Compound Interest?
(a) 5%
(b) 10%
(c) 8%
(d) 12%
Answer: (b) 10%
Logic:
√(2420 / 2000) = √(121 / 100) = 11 / 10
Money grows from 10 to 11
Rate = 10%
Q8. Simple Interest on a sum for 3 years at 10% is ₹300. Find the Compound Interest on the same sum for 2 years at the same rate.
(a) ₹200
(b) ₹210
(c) ₹220
(d) ₹205
Answer: (b) ₹210
Logic:
SI per year = 300 / 3 = 100
Principal = 100 × 100 / 10 = 1000
CI for 2 years = 100 + 100 + Interest on 100
= 210
Q9. A sum becomes 3 times itself in 5 years at Simple Interest. In how many years will it become 9 times?
(a) 15 years
(b) 20 years
(c) 12 years
(d) 10 years
Answer: (b) 20 years
Logic:
To become 3 times → Interest = 2P in 5 years
To become 9 times → Interest = 8P
8P is 4 times of 2P
Time = 5 × 4 = 20 years
Q10. What is the amount if interest is compounded half-yearly on ₹10,000 for 1 year at 20% per annum?
(a) ₹12,000
(b) ₹12,100
(c) ₹11,000
(d) ₹12,500
Answer: (b) ₹12,100
Logic:
Half-yearly compounding:
Rate = 10%, Time = 2 half-years
1st half-year interest = 1000
2nd half-year interest = 1100
Amount = 10000 + 1000 + 1100 = ₹12,100
Here are some tips and tricks that will help you solve simple and compound interest questions easily.
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No. The level is matriculation (10th pass). The questions are formula-based and very direct.
You can expect around 2 to 3 questions in the Elementary Mathematics section.
Yes! Using the “100 Method” (Assuming Principal as 100) or Fraction Method is much faster and easier than using X.
You can download the free, exam-level PDF by clicking the link provided in the middle of this blog post.
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