Are you finding Problems on Ages a little tricky? You are not alone. Many RBI Grade B aspirants feel the same. These questions may look simple, but they need a proper method. With the right tricks, you can solve them in seconds. And you can save that extra time for tougher questions like DI. In the RBI Grade B Phase 1 exam, Quantitative Aptitude carries 30 marks. Problems on Ages usually carry 1 or 2 marks. As per past exams, the difficulty level is easy to moderate. This means you can maximize your score through this topic. But you must know the correct approach. In most cases, you can solve these in under 40 seconds if you follow some basic rules. In this article, we’ll share the types of Problems on Ages, the formulas you must know, the tricks to solve them fast, and some practice examples based on the RBI Grade B exam pattern.
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Let’s first understand the common types of questions that appear in the exam.
Here, the question talks about current ages. You simply form equations and solve.
For example, A is twice B’s age today. Four years from now, their total age will be 50. Find their current ages.
These are the most common type and the easiest to solve.
Sometimes, the ages are given as a ratio. You may also get the ratio for two different time periods.
For example, A : B = 4 : 5 today. After 6 years, A : B = 5 : 6. Find their present ages.
Ratios help you find actual ages quickly if you know the total or the difference.
These talk about ages some years ago.
For example: Five years ago, A was three times B. Find their present ages.
Here, you need to work backwards to solve such questions.
These give conditions about ages after some years.
For example, after 8 years, A will be twice B. Find their present ages.
These mix present, past, and future data in one question.
For example: “A’s age five years ago was twice B’s age ten years ago…”
You need to be patient and solve such questions in steps.
To solve all the questions mentioned above, you need to master some basics and formulas. Let’s discuss them!
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Formulas are the routes that take you to the solution of a problem. Here are some rules you must keep in mind for every question:
The difference in ages never changes. If A is 10 years older than B today (the 10-year gap will always remain there in between them), A will be 10 years older in the future as well as in the past.
If two people’s ages sum to S today, after n years their sum will be S + 2n.
For three people, add 3n instead.
If you know the ratio and the total sum:
Actual Age = (Ratio Part ÷ Total Parts) × Total Sum.
Change statements into equations quickly.
For example: “Four years later, A will be twice B” → A + 4 = 2(B + 4).
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Here’s a tested approach that works for RBI Grade B questions.
Example 1 – Present Age Based
The present age of A is twice that of B. Four years later, the sum of their ages will be 50. Find their present ages.
Let B = x, A = 2x.
(2x + 4) + (x + 4) = 50
3x + 8 = 50 → 3x = 42 → x = 14
A = 28, B = 14
Answer: A = 28 years, B = 14 years
Example 2 – Ratio Based
The ratio of A’s age to B’s age is 4:5. The ratio will be 5:6 after 6 years. Find their present ages.
Let A = 4k and B = 5k
(4k + 6)/(5k + 6) = 5/6
24k + 36 = 25k + 30 → k = 6
A = 24, B = 30
Answer: A = 24 years, B = 30 years
Example 3 – Past Age Based
A was three times B five years ago. Find A’s present-day age if B is now 15 years old.
Five years ago: B = 10
A then = 3 × 10 = 30
Now A = 30 + 5 = 35
Answer: A = 35 years
Daily practice is the key to mastering Problems on Ages.
Try these:
Problems on Ages is one of the easiest topics in the RBI Grade B Quant section. The rules are simple. The methods are quick. Once you learn the difference rule, the equation method, and the ratio approach, you can score these marks with full accuracy. Make this topic a part of your daily practice. Secure these marks in the real exam and save time for the tougher ones.
Usually 1 to 2 marks.
Use the constant age difference rule.
Yes, mostly easy to moderate.
Upu should invest under 40 seconds in solving one question.
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