SBI PO

Inequalities questions for SBI PO

Inequality questions are an important part of the Reasoning section in SBI PO exams. While they are not asked in the Mains stage, they are consistently featured in the Prelims and should not be ignored. Mastering this topic can help you secure quick and easy marks, making it a smart area to focus on during your preparation.

👉 For the latest updates on exam dates, eligibility, and application process, check the detailed SBI PO Notification before starting your preparation.

Inequalities questions for SBI PO 2021 Prelims Practice

Cracking topics like Inequalities can significantly improve your Prelims score and bring you closer to securing the attractive SBI PO Salary package offered to Probationary Officers.

Question 1: In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and then give your answer accordingly.

Statements: Y>O≥S≤T; S ≥ K≥H < V

Conclusions:

I. Y>V

II. T ≥H

III. H≤O

a. Only conclusion I is true.

b. Only conclusions I and III are true.

c. Only conclusion II is true.

d. Only conclusions II and III are true.

e. All conclusions I, II and III are false.

Answer: d

Solution:

Given statements: Y>O≥S≤T; S ≥ K≥H < V

On combining, we get

Y>O≥S ≥ K≥H < V; T ≥ S ≥ K≥H < V

Conclusions:

I. Y>V: False (As Y>O≥S ≥ K≥H < V, the relation between Y and V cannot be determined)

II. T≥H: True (As T ≥ S ≥ K≥H, so, T≥H)

III. H≤O: True (As O≥S ≥ K≥H, so, O ≥ H)

Hence, option d.

Question 2: In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and then give your answer accordingly.

Statements: B ≥ K = T; X < B ≤ M; G > K > F

Conclusions:

I. F < X

II. M ≥ K

III. B > F

a. Only conclusion I is true.

b. Only conclusions II and III are true.

c. Only conclusion II is true.

d. Only conclusions I and II are true.

e. All conclusions I, II and III are false.

Answer: b

Solution:

Given statements: B ≥ K = T; X < B ≤ M; G > K > F

On combining, we get

X < B ≥ K > F; T = K ≤ B > X; M ≥ B ≥ K > F

Conclusions:

I. F < X: False (As X < B ≥ K > F, the relation between F and X can’t be determined)

II. M ≥ K: True (As M ≥ B ≥ K, so M ≥ K)

III. B > F: True (As B ≥ K > F, so B > F)

Hence, option b.

Question 3: Which of the following should be placed in the blank spaces respectively ( in the same order from left to right) in order to complete the given expression in such a manner that makes the expression ‘P > Q’ definitely false?

__ > __ < __ ≤ __ > __ ≤ __

a. U, T, P, S, R, Q

b. P, T, S, Q, R, U

c. T, P, U, Q, S, R

d. P, R, Q, T, S, U

e. None of the above

Answer: c

Solution:

i. Putting the option (a) values to the equation, we get U > T < P ≤ S > R ≤ Q, here P > Q is not definitely false.

ii. Putting the option (b) values to the equation, we get P > T < S ≤ Q > R ≤ U, here P > Q is not definitely false.

iii. Putting the option (c) values to the equation, we get T > P < U ≤ Q > S ≤ R, here P > Q is definitely false.

iv. Putting the option (d) values to the equation, we get P > R < Q ≤ T > S ≤ U, here P > Q is not definitely false.

Hence, option c.

Question 4: Which of the following symbols should replace the question marks (?) in the given expression in order to make the expressions ‘A ≥ C’ definitely true?

G > C (?) E ≤ D; B > A ≥ D

a. ≥

b. <

c. >

d. None of these

e. ≤

i. Replacing the signs of option (a) in the given inequality, G > C ≥ E ≤ D; B > A ≥ D, it doesn’t satisfy the given condition.

ii. Replacing the signs of option (c) in the given inequality, G > C < E ≤ D; B > A ≥ D, it doesn’t satisfy the given condition.

iii. Replacing the signs of option (d) in the given inequality, G > C > E ≤ D; B > A ≥ D, it doesn’t satisfy the given condition.

iv. Replacing the signs of option (e) in the given inequality, G > C ≤ E ≤ D; B > A ≥ D, it satisfies the given condition.

Hence, option e.

Disclaimer: The Inequalities Questions for SBI PO provided on PracticeMock’s blog are intended solely for educational and exam-preparation purposes. These questions and explanations are not official materials released by the State Bank of India (SBI) or the Institute of Banking Personnel Selection (IBPS) and should not be considered a substitute for official exam papers or notifications. While efforts have been made to ensure accuracy and relevance, PracticeMock does not guarantee that the questions, formats, or difficulty levels will exactly match those in the actual examination. Readers are strongly advised to consult SBI/IBPS’s official website and notifications for authoritative information. PracticeMock and its contributors disclaim responsibility for any errors, omissions, or outcomes resulting from reliance on this material.

CODED INEQUALITIES:

Directions (5-6): Answer the questions based on the information given below.

If ‘>’ is denoted as ‘#’

‘≥’ is denoted as ‘&’

‘=’ is denoted as ‘$’

‘≤’ is denoted as ‘%’

And ‘<’ is denoted as ‘@’

Question 5: Statement: O&N#P$S; N@R$L%T; L#Q$U

Conclusions:

I. Q # P

II. U @ T

III. R # T

a. Only conclusion I is true.

b. Only conclusion II is true

c. Either conclusion I or III and II are true

d. Both conclusions II and III are true.

e. All the conclusions I, II and III are true.

Answer: b

Solution:

Decoding the signs of the statements, statement becomes

O ≥ N > P = S; N < R = L ≤ T; L > Q = U

On combining, we get

Q < L = R > N > P and T ≥ L > Q = U

Conclusions:

I. Q # P means Q > P: False (As, Q < L = R > N > P)

II. U @ T means U < T: True (As, T ≥ L > Q = U)

III. R # T means R > T: False (As, R = L ≤ T, so, R ≤ T)

Hence option b.

Question 6: Statement: R@U%Q$T; Q#L&M; N$M@O

Conclusions:

I. R @ M

II. Q # N

III. L $ T

a. Only conclusion I is true.

b. Only conclusion II is true

c. Only conclusions I and II is true

d. Only conclusions I and III are true.

e. All conclusion I, II and III are true.

Answer: b

Solution:

Decoding the signs of the statements, statement becomes

R < U ≤ Q = T; Q > L ≥ M; N = M < O

On combining, we get

R< Q > M and N = M ≤ L < Q = T

Conclusions:

I. R @ M means R < M: False (As, R< Q > M)

II. Q # N means Q > N: True (As, N = M ≤ L < Q = T)

III. L $ T means L = T: False (As, N = M ≤ L < Q = T)

Hence option b.

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