Coding-Decoding Questions for RRB NTPC: Download Free PDF & Practice Now
Preparing for the RRB NTPC exam? You know that the General Intelligence and Reasoning is one of the best sections to score high marks. Unlike Math, you don’t need long calculations. Unlike GK, you don’t need to memorize dates. Still, most candidates fail to score good marks in this section because they don’t prepare the most scoring topics. One of the most popular topics in Reasoning is Coding-Decoding.
At first glance, seeing a question like “If DELHI is coded as CCIDD, how is BOMBAY coded?” might look like a secret spy message. But don’t worry. You don’t need to be James Bond to solve this.
Here is the secret: Coding-Decoding is just a game of patterns. The examiner simply shifts letters forward or backward (like A becomes B, or A becomes Z). Once you understand the rule, you can solve these questions in 10-15 seconds. To help you master this topic, we have collected the most repeated Coding-Decoding questions from previous Railway exams. We have compiled them into a free PDF that you can download from this blog.
In both CBT-1 and CBT-2, this topic is a goldmine for marks.
You will mostly see three types of questions in the exam:
We have analyzed many previous years’ question papers to understand the types of questions RRB asks in the exam. After carefully analysing those papers, we have created a PDF in which we have provided the most repeated, asked, and exam-level questions. You can download this PDF for free and start practicing for the exam.
Q1. In a certain code, ‘TEACHER’ is written as ‘VGCEJGT’.
How is ‘CHILDREN’ written in that code?
(a) EJKNFTGP
(b) EJKNFGTO
(c) EJKNEGTP
(d) EJKNFTGO
Answer: (a) EJKNFTGP
Logic:
Each letter is shifted +2 in the alphabet.
T + 2 = V, E + 2 = G, A + 2 = C …
Similarly, C + 2 = E, H + 2 = J, I + 2 = K, L + 2 = N, D + 2 = F, R + 2 = T, E + 2 = G, N + 2 = P.
Q2. If ‘RACKET’ is written as ‘813524’, how is ‘TRACK’ written in that code?
(a) 24138
(b) 42138
(c) 41238
(d) 21438
Answer: (b) 42138
Logic:
Direct letter coding based on RACKET:
R = 8, A = 1, C = 3, K = 5, E = 2, T = 4.
So, TRACK = T R A C K = 4 2 1 3 8 → 42138.
Q3. If Z = 52 and ACT = 48, then BAT will be equal to:
(a) 39
(b) 41
(c) 44
(d) 46
Answer: (d) 46
Logic:
Z = 26 × 2 = 52
ACT = (1 + 3 + 20) × 2 = 24 × 2 = 48
BAT = (2 + 1 + 20) × 2 = 23 × 2 = 46
Q4. If ‘WATER’ is written as ‘YCVGT’, then what is written as ‘HKTG’?
(a) IRFE
(b) FIRE
(c) REFI
(d) ERIF
Answer: (b) FIRE
Logic:
Each letter is shifted +2.
To decode, shift –2:
H – 2 = F, K – 2 = I, T – 2 = R, G – 2 = E → FIRE
Q5. In a certain code language:
‘134’ means good and tasty
‘478’ means see good pictures
‘729’ means pictures are faint
Which digit stands for ‘see’?
(a) 9
(b) 2
(c) 1
(d) 8
Answer: (d) 8
Logic:
‘Good’ appears in first and second → common digit = 4
‘Pictures’ appears in second and third → common digit = 7
In ‘478’, remaining word is ‘see’ → remaining digit = 8
Q6. If ROSE is coded as 6821, CHAIR as 73456, and PREACH as 961473, what will be the code for SEARCH?
(a) 246173
(b) 214673
(c) 214763
(d) 216473
Answer: (b) 214673
Logic:
Direct letter coding:
S = 2, E = 1, A = 4, R = 6, C = 7, H = 3
SEARCH = 214673
Q7. If A = 26 and SUN = 27, then CAT = ?
(a) 24
(b) 27
(c) 57
(d) 58
Answer: (c) 57
Logic:
Reverse alphabet values (A = 26, Z = 1)
SUN → S = 8, U = 6, N = 13 → 8 + 6 + 13 = 27
CAT → C = 24, A = 26, T = 7 → 24 + 26 + 7 = 57
Q8. In a certain code, ‘MONKEY’ is written as ‘XDJMNL’.
How is ‘TIGER’ written in that code?
(a) QDFHS
(b) SDFHS
(c) SHFDQ
(d) UJHFS
Answer: (a) QDFHS
Logic:
First reverse the word, then subtract 1 from each letter.
MONKEY → YEKNOM → XDJMNL
TIGER → REGIT → QDFHS
Q9. If:
SKY is called SEA,
SEA is called WATER,
WATER is called AIR,
AIR is called CLOUD,
CLOUD is called RIVER,
Where do we fly an aeroplane?
(a) WATER
(b) CLOUD
(c) AIR
(d) RIVER
Answer: (b) CLOUD
Logic:
We fly an aeroplane in AIR, but AIR is called CLOUD.
Q10. If E = 5 and HOTEL = 12, then how will you code LAMB?
(a) 7
(b) 10
(c) 26
(d) 28
Answer: (a) 7
Logic:
HOTEL → (8 + 15 + 20 + 5 + 12) = 60
Number of letters = 5 → 60 ÷ 5 = 12
LAMB → (12 + 1 + 13 + 2) = 28
Number of letters = 4 → 28 ÷ 4 = 7
Here, we have provided some tips and tricks to solve coding-decoding questions easily in the exam.
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No. It is one of the easiest topics to discuss. The logic is usually straightforward (+1 or -1).
You can consistently expect 3 to 5 questions in the Reasoning section.
It helps a lot! If you know M=13 and W=23, you save 10-20 seconds per question. Use the EJOTY trick.
You can download the free, exam-level PDF by clicking the link provided in the middle of this blog post.
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