SSC CHSL exam is one of the most prestigious exams for youth in India. But getting selected for this post is not an easy task. Candidates do a lot of practice for this exam, but most of them fail due to one section, which is the quantitative aptitude section. Keeping this in mind, and to increase your chances of success, we have provided this blog. In which we have provided a PDF containing exam-level questions for one of the most scoring topics, which is simple and compound interest. You can download the PDF of questions on simple and compound interest for SSC CHSL exam.
In the quantitative aptitude section, you will find 15 questions. Out of these, 2 questions are almost guaranteed to be from Simple or Compound Interest.
We have analyzed the papers from previous recruitments to find the exact level of questions asked. We have put them all in one PDF. Download it, save it, and practice these questions to build confidence.
Q1. Find the Simple Interest on ₹5000 at 10% per annum for 3 years.
(a) ₹1000
(b) ₹1500
(c) ₹2000
(d) ₹1200
Answer: (b) ₹1500
Logic:
Formula:
SI = (P × R × T) / 100
= (5000 × 10 × 3) / 100
= ₹1500
Q2. At what rate percent per annum will a sum of money double itself in 10 years at Simple Interest?
(a) 8%
(b) 10%
(c) 12%
(d) 5%
Answer: (b) 10%
Logic:
To double, Interest = Principal (P).
P = (P × R × 10) / 100
R = 10%
Q3. Find the Compound Interest on ₹4000 for 2 years at 5% per annum.
(a) ₹400
(b) ₹410
(c) ₹420
(d) ₹450
Answer: (b) ₹410
Logic:
5% of 4000 = 200 (1st year)
Amount after 1st year = 4000 + 200 = 4200
5% of 4200 = 210 (2nd year)
Total CI = 200 + 210 = ₹410
Q4. The difference between CI and SI on a certain sum for 2 years at 10% per annum is ₹20. Find the sum.
(a) ₹1000
(b) ₹2000
(c) ₹3000
(d) ₹1500
Answer: (b) ₹2000
Logic:
Difference for 2 years:
D = P(R/100)²
20 = P(10/100)²
20 = P(1/100)
P = ₹2000
Q5. A sum of money becomes ₹7200 in 2 years and ₹8400 in 3 years at Compound Interest. Find the rate of interest.
(a) 10.66%
(b) 12.5%
(c) 15%
(d) 16.66%
Answer: (d) 16.66%
Logic:
Interest earned in 1 year = 8400 − 7200 = 1200
Rate = (1200 / 7200) × 100 = 16.66%
Q6. In how many years will ₹1200 become ₹1344 at 6% Simple Interest?
(a) 2 years
(b) 3 years
(c) 2.5 years
(d) 1.5 years
Answer: (a) 2 years
Logic:
Interest = 1344 − 1200 = 144
144 = (1200 × 6 × T) / 100
144 = 72T
T = 2 years
Q7. What will be the Compound Interest on ₹10,000 for 2 years at 10% per annum, compounded half-yearly?
(a) ₹2100
(b) ₹2155.06
(c) ₹2000
(d) ₹2200
Answer: (b) ₹2155.06
Logic:
Half-yearly compounding:
Rate = 5%
Time = 4 half-years
This is usually solved using the compound amount formula or effective rate method.
Q8. A sum becomes 3 times itself in 5 years at Simple Interest. In how many years will it become 5 times?
(a) 8 years
(b) 10 years
(c) 12 years
(d) 9 years
Answer: (b) 10 years
Logic:
To become 3 times → Interest = 2P in 5 years
To become 5 times → Interest = 4P
Time doubles → 10 years
Q9. If the Simple Interest for 2 years is ₹400 and the Compound Interest for the same period and rate is ₹410, find the rate of interest.
(a) 4%
(b) 5%
(c) 10%
(d) 8%
Answer: (b) 5%
Logic:
SI for 1 year = 200
Difference between CI and SI = 10
10 is interest on ₹200
Rate = (10 / 200) × 100 = 5%
Q10. Find the Amount if P = ₹2500, R = 4%, T = 2 years (Simple Interest).
(a) ₹2600
(b) ₹2700
(c) ₹2800
(d) ₹2550
Answer: (b) ₹2700
Logic:
SI = (2500 × 4 × 2) / 100 = 200
Amount = 2500 + 200 = ₹2700
Solving simple and compound interest questions can be tough, but using tips and tricks can make solving these questions easy. Below, we have mentioned some tips that will help you solve these questions easily.
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No, it is on the 12th level. The questions are direct and formula-based.
You can expect at least 2 questions from this topic in the Numerical Ability section.
Yes, if you are good with percentages. For example, 10% for 2 years in CI is effectively 21% total interest. Using this percentage method is faster.
You can download the free, exam-level PDF by clicking the link provided in the middle of this blog post
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