Quadratic Equations for RRB Clerk 2025: Check Important Questions and Tips to Solve

Do you want to score high in the Quant section of the RRB Clerk 2025 exam? Then don’t ignore Quadratic Equations. This topic may look tricky at first, but it is easy and scoring with the right practice. These questions are quick to solve and usually follow a fixed pattern. Quadratic questions are one of the highest-scoring topics in the prelims of the RRB Clerk exam. Read this blog to know the type of quadratic equations questions asked in the exam and how to solve them easily. 

What Are Quadratic Equations?

A quadratic equation is a mathematical expression in the form:

  ax² + bx + c = 0

Here, a, b, and c are numbers, and x is the unknown variable.

What you have to do is find the values of x that satisfy the equation. These values are also known as the roots of the equation.

Weightage and Importance of Quadratic Equations in RRB Clerk Exam

You will get 4-5 questions on the quadratic equations in the RRB Clerk Prelims exam. This means solving just one small set of these questions correctly can give you a straight 5 marks.

The best part is that these questions are direct, formula-based, and do not involve lengthy calculations. Once you understand how to factor and compare roots, it becomes one of the quickest and most accurate topics to attempt in your paper.

Most Important Quadratic Equations Questions for RRB Clerk 2025

Here we are providing the most important Quadratic Equations RRB Clerk questions. Candidates can click the PDF link and attempt all the questions.

Question 1: In the questions, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.

I. y³ = –512

II. x² + 14x + 49 = 0

A) x > y

B) x < y

C) x = y or the relationship cannot be established

D) x ≥ y

E) x ≤ y

Question 2: In the questions, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.

I. x = (1331)^1/3

II. y² – 19y + 88 = 0

A) x > y

B) x < y

C) x = y or the relationship cannot be established

D) x ≥ y

E) x ≤ y

Question 3: In the questions, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.

I. x² – 2x – 15 = 0

II. y² + 2y – 15 = 0

A) x > y

B) x < y

C) x = y or the relationship cannot be established

D) x ≥ y

E) x ≤ y

Question 4: In the questions, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.

I. 3x + 2y = 41

II. 4x + 5y = 71

A) x = y or the relationship cannot be established

B) x < y

C) x > y

D) x ≥ y

E) x ≤ y

Question 5: In the questions, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.

I. x² – 9x + 20 = 0

II. y² – 8y + 20 = 3y – 10

A) x > y

B) x < y

C) x = y or the relationship cannot be established

D) x ≥ y

E) x ≤ y

Quadratic Equations Questions PDF

An example of Quadratic Equations with questions and answers in PDF format is provided below. Download now.

Tips to Solve Quadratic Equation Questions

We are providing some basic and simple tips to solve quadratic equations. Let’s look at some  tips to help you master this topic:

Know the Basic Formula First

The standard form of a quadratic equation is:
  ax² + bx + c = 0

You can solve it in two ways:

• Factorization method (breaking the middle term)
  
• Quadratic formula:
  x = [-b ± √(b² – 4ac)] / 2a
  (You rarely need this in exams, but it’s good to know.)
  

Practice Breaking the Middle Term

This is the most commonly used method.

Let’s solve:
x² + 5x + 6 = 0

We need to find two numbers that:

• Multiply by: 6 (i.e., product = +6)
  
• Add up to: 5 (i.e., sum = +5)
  

Let’s check different pairs of factors of 6:

1. +2 and +3
    Product = 2 × 3 = 6
   Sum = 2 + 3 = 5 Correct
   
2. -2 and -3
    Product = (-2) × (-3) = 6
   Sum = -2 + (-3) = -5 Wrong
   
3. +1 and +6
    Product = 1 × 6 = 6
   Sum = 1 + 6 = 7 Wrong
   
4. -1 and -6
    Product = (-1) × (-6) = 6
   Sum = -1 + (-6) = -7 Wrong
   

So, the only correct pair is:
 +2 and +3

Now split the middle term (5x) using these numbers:
x² + 2x + 3x + 6 = 0

Group and factor:
(x² + 2x) + (3x + 6) = 0
x(x + 2) + 3(x + 2) = 0
(x + 2)(x + 3) = 0

So the roots are:
x = -2 and x = -3

Compare Roots Correctly

Once you solve both x and y equations, compare all possible values.

Example:
x = -2, -3 and y = -1, -4
Now compare:

• Is x always greater than y?
  
• Or sometimes greater and sometimes smaller?
  

Only then choose the correct option (A to E).

Avoid Silly Mistakes

Always double-check your factorization method, root signs, and comparison if you are comparing values of x and y. Check carefully because a small mistake can make your final answer wrong. 

Skip the Tough Ones (if needed)

If you’re not getting a factor easily within 15–20 seconds, skip and move on. You can come back later. Don’t waste time on a tough one and miss out on easy marks elsewhere.

Practice Every Day

Just solve 5–10 quadratic questions daily. In 10 days, you will get the pattern. Most questions repeat similar logic. Practice also helps reduce pressure during the real exam.

Disclaimer: The quadratic equation questions, tips, and solutions provided are for practice and guidance only. They are illustrative, not official IBPS RRB Clerk exam content. Actual exam questions may vary in wording, format, or difficulty. Candidates should always consult official IBPS notices for authentic and updated information.

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