Algebra Questions for RRB NTPC Download Free PDF
Dreaming of a job in the Indian Railways? Whether you want to be a clerk or a Station Master, the RRB NTPC exam is your golden ticket. But to get that ticket, you have to cross the hurdle of Mathematics. Many students get scared when they see Algebra questions with x, y, and z. They think they need a lot of practice, but Algebra in RRB NTPC is actually very simple. It is not as complex as other exams. It is purely based on a few fixed formulas. If you memorize just 5 or 6 standard identities, you can solve these questions in seconds without any confusion. To help you prepare smart, we have analyzed previous Railway papers and created a PDF in which we have provided the most important Algebra questions for RRB NTPC.
In both CBT-1 and CBT-2, Advanced Math plays a huge role, and Algebra is a major part of it.
You don’t need to study the whole book. RRB mostly asks questions from these specific areas:
We have prepared a comprehensive PDF containing exam-level questions. We have chosen questions that match the exact difficulty level of RRB NTPC—tricky but logical. Download it, save it, and practice these questions to remove your fear of variables.
Q1. If x + 1/x = 5, find the value of x^3 + 1/x^3.
(a) 125
(b) 110
(c) 115
(d) 140
Answer: (b) 110
Logic: Formula is k^3 − 3k. Here k = 5.
5^3 − 3(5) = 125 − 15 = 110.
Q2. If a + b + c = 0, find the value of a^2/bc + b^2/ca + c^2/ab.
(a) 0
(b) 1
(c) 3
(d) −1
Answer: (c) 3
Logic: Taking LCM as abc, the numerator becomes a^3 + b^3 + c^3.
Since a + b + c = 0, a^3 + b^3 + c^3 = 3abc.
So value = 3abc / abc = 3.
Q3. If x = 7 − 4√3, find the value of x + 1/x.
(a) 14
(b) 8
(c) 8√3
(d) 7
Answer: (a) 14
Logic: 1/x = 7 + 4√3 (conjugate).
Adding: (7 − 4√3) + (7 + 4√3) = 14.
Q4. Find the roots of the quadratic equation x^2 − 7x + 12 = 0.
(a) 3, 4
(b) −3, −4
(c) 2, 5
(d) 6, 1
Answer: (a) 3, 4
Logic: Numbers multiplying to 12 and adding to −7 are −3 and −4.
Roots are x = 3 and x = 4.
Q5. If a^2 + b^2 + 1/a^2 + 1/b^2 = 4, find the value of a^2 + b^2.
(a) 1
(b) 2
(c) 4
(d) 0
Answer: (b) 2
Logic: This is possible only when a^2 = 1 and b^2 = 1.
So a^2 + b^2 = 1 + 1 = 2.
Q6. If x/y = 3/4, find the value of (2x + 3y) / (3y − 2x).
(a) 3
(b) 2
(c) 1
(d) 4
Answer: (a) 3
Logic: Take x = 3 and y = 4.
Numerator = 2(3) + 3(4) = 18
Denominator = 3(4) − 2(3) = 6
Value = 18/6 = 3.
Q7. If x + y = 4 and x − y = 2, find the value of x^2 − y^2.
(a) 6
(b) 8
(c) 12
(d) 16
Answer: (b) 8
Logic: x^2 − y^2 = (x + y)(x − y)
= 4 × 2 = 8.
Q8. If (x − 3)^2 + (y − 5)^2 + (z − 4)^2 = 0, find (x + y) / z.
(a) 1
(b) 2
(c) 3
(d) 4
Answer: (b) 2
Logic: Each square must be zero.
x = 3, y = 5, z = 4
(x + y)/z = 8/4 = 2.
Q9. If x + 1/x = 2, find x^17 + 1/x^19.
(a) 2
(b) 0
(c) 1
(d) −2
Answer: (a) 2
Logic: x + 1/x = 2 implies x = 1.
1^17 + 1/1^19 = 2.
Q10. The factors of x^2 + x − 20 are:
(a) (x + 5)(x − 4)
(b) (x − 5)(x + 4)
(c) (x + 2)(x − 10)
(d) (x − 2)(x + 10)
Answer: (a) (x + 5)(x − 4)
Logic: Numbers multiplying to −20 and adding to +1 are +5 and −4.
Don’t calculate everything. Use smart tricks to save time.
No. It is formula-based. If you know the basic identities like (a+b)^3, you can solve it easily.
You can consistently expect 2 to 3 questions in CBT-1 and slightly more in CBT-2.
It is a shortcut where you replace variables (x, y, z) with simple numbers (like 0 or 1) to find the answer without solving the full equation.
You can download the free, exam-level PDF by clicking the link provided in the middle of this blog post.
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