{"id":9889,"date":"2021-10-21T13:03:11","date_gmt":"2021-10-21T07:33:11","guid":{"rendered":"https:\/\/www.practicemock.com\/blog\/?p=9889"},"modified":"2021-10-21T13:03:11","modified_gmt":"2021-10-21T07:33:11","slug":"number-series-for-sbi-po","status":"publish","type":"post","link":"https:\/\/www.practicemock.com\/blog\/number-series-for-sbi-po\/","title":{"rendered":"Number Series for SBI PO with Q&#038;A"},"content":{"rendered":"\n<p>Number Series for SBI PO: The topic of number series is very popular amongst the SBI PO aspirants. We receive a lot of messages regarding number series doubts and practice questions. So, here we are today to deliver on the same. <\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Number Series for SBI PO Tips &amp; Tricks&nbsp;&nbsp;<\/h2>\n\n\n\n<p>A question of number\/wrong terms series&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p>Direction: Find the wrong term in the given series: 800, 678, 579, 497, 434, 385, 349&nbsp;&nbsp;<\/p>\n\n\n\n<ol class=\"wp-block-list\"><li>494&nbsp;&nbsp;<\/li><li>385&nbsp;&nbsp;<\/li><li>800&nbsp;&nbsp;<\/li><li>579&nbsp;&nbsp;<\/li><li>349&nbsp;&nbsp;<\/li><\/ol>\n\n\n\n<p>Things to learn:&nbsp;&nbsp;<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>Logics \u2013 Notice the pattern of the series. If it\u2019s based on addition, subtraction, cubes, square, etc.&nbsp;&nbsp;<\/li><li>Sequence to implement these logics \u2013 Follow a step-based protocol for recognizing the sequence.&nbsp;&nbsp;<\/li><\/ul>\n\n\n\n<p>Step-based protocol for sequences (Missing terms)&nbsp;&nbsp;<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>Check if the sequence is based on square, cube, square +, sqaure -, cube +, cube \u2013&nbsp;&nbsp;<\/li><li>Check if the sequence is based on Multiplication +-, Division +-&nbsp;&nbsp;<\/li><li>Look for double\/triple series is being used&nbsp;&nbsp;<\/li><li>Look for illogical series is given (rarely given)&nbsp;&nbsp;<\/li><\/ul>\n\n\n\n<p>Now look for logic as well during these steps. However, for the wrong term series, you can directly just follow the steps.<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><a href=\"https:\/\/www.practicemock.com\/exams\/banking\/sbi-po\/?refcode=2918&amp;utm_source=Blog_Number+Series+for+SBI+PO+with+Q%26A_191021_SBIPM&amp;utm_medium=Link&amp;utm_campaign=SBIPM\"><img decoding=\"async\" src=\"https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2021\/09\/SBI_PO_270821-1024x128.jpg\" alt=\"Number Series for SBI PO \" class=\"wp-image-7629\"\/><\/a><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\">Number Series for SBI PO &#8211; Questions with Answers<\/h2>\n\n\n\n<p>Q1.) In the question, three series I, II and III are given. Find the value of x, y and z to establish the correct relation among them and choose the correct option.&nbsp;<\/p>\n\n\n\n<p>(i) 118,&nbsp;x,&nbsp;136, 160, 208, 304&nbsp;<\/p>\n\n\n\n<p>(ii) 945, y, 60, 24, 16, 32&nbsp;<\/p>\n\n\n\n<p>(iii) 138, 131, 145, z, 152, 117&nbsp;<\/p>\n\n\n\n<p>a.)&nbsp;x = y &gt; z&nbsp;<\/p>\n\n\n\n<p>b.)&nbsp;x &gt; y = z&nbsp;<\/p>\n\n\n\n<p>c.)&nbsp;x = z &lt; y&nbsp;<\/p>\n\n\n\n<p>d.)&nbsp;y &gt; x &lt; z&nbsp;<\/p>\n\n\n\n<p>e.)&nbsp;x = y = z&nbsp;<\/p>\n\n\n\n<p><strong>Answer:&nbsp;c)<\/strong>&nbsp;<\/p>\n\n\n\n<p><strong>Solution:<\/strong>&nbsp;<\/p>\n\n\n\n<p>Series I follow the pattern as:&nbsp;<\/p>\n\n\n\n<p><strong>118 + 6 \u00d7 1 = 124<\/strong>&nbsp;<\/p>\n\n\n\n<p>124 + 6 \u00d7 2 = 136&nbsp;<\/p>\n\n\n\n<p>136 + 6 \u00d7 4 = 160&nbsp;<\/p>\n\n\n\n<p>160 + 6 \u00d7 8 = 208&nbsp;<\/p>\n\n\n\n<p>208 + 6 \u00d7 16 = 304&nbsp;<\/p>\n\n\n\n<p>So, x = 124&nbsp;<\/p>\n\n\n\n<p>Series II follow the pattern as:&nbsp;<\/p>\n\n\n\n<p>210 \u00d7 4.5 = 945&nbsp;<\/p>\n\n\n\n<p><strong>60 \u00d7 3.5 = 210<\/strong>&nbsp;<\/p>\n\n\n\n<p>24 \u00d7 2.5 = 60&nbsp;<\/p>\n\n\n\n<p>16 \u00d7 1.5 = 24&nbsp;<\/p>\n\n\n\n<p>32 \u00d7 0.5 = 16&nbsp;<\/p>\n\n\n\n<p>So, y = 210&nbsp;<\/p>\n\n\n\n<p>Series III follow the pattern as:&nbsp;<\/p>\n\n\n\n<p>138 \u2013 7 = 131&nbsp;<\/p>\n\n\n\n<p>131 + 14 = 145&nbsp;<\/p>\n\n\n\n<p><strong>145 \u2013 21 = 124<\/strong>&nbsp;<\/p>\n\n\n\n<p>124 + 28 = 152&nbsp;<\/p>\n\n\n\n<p>152 \u2013 35 = 117&nbsp;<\/p>\n\n\n\n<p>So, z = 124&nbsp;<\/p>\n\n\n\n<p>Therefore, x = z &lt; y&nbsp;<\/p>\n\n\n\n<p>Hence, option c.&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image\"><a href=\"https:\/\/www.practicemock.com\/exams\/banking\/sbi-po\/?refcode=2918&amp;utm_source=Blog_Number+Series+for+SBI+PO+with+Q%26A_191021_SBIPM&amp;utm_medium=Link&amp;utm_campaign=SBIPM\"><img decoding=\"async\" src=\"https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2021\/09\/SBI_PO_270821-1024x128.jpg\" alt=\"Number Series for SBI PO \"\/><\/a><\/figure>\n\n\n\n<p>Q2.) A&nbsp;numbers 17, 21, 30, 55, 104, 225 forms a series.&nbsp;<\/p>\n\n\n\n<p>If 2414 is the n<sup>th<\/sup>&nbsp;term of the above given series, then find the value of n.&nbsp;<\/p>\n\n\n\n<p>a.)&nbsp;9&nbsp;<\/p>\n\n\n\n<p>b.)&nbsp;13&nbsp;<\/p>\n\n\n\n<p>c.)&nbsp;12&nbsp;<\/p>\n\n\n\n<p>d.)&nbsp;10&nbsp;<\/p>\n\n\n\n<p>e.)&nbsp;11&nbsp;<\/p>\n\n\n\n<p><strong>Answer:&nbsp;e)<\/strong>&nbsp;<\/p>\n\n\n\n<p><strong>Solution:<\/strong>&nbsp;<\/p>\n\n\n\n<p>We are adding square of consecutive prime numbers starting with 2.&nbsp;<\/p>\n\n\n\n<p>17 + 2<sup>2<\/sup>&nbsp;= 21&nbsp;<\/p>\n\n\n\n<p>21 + 3<sup>2<\/sup>&nbsp;= 30&nbsp;<\/p>\n\n\n\n<p>30 + 5<sup>2<\/sup>&nbsp;= 55&nbsp;<\/p>\n\n\n\n<p>55 + 7<sup>2<\/sup>&nbsp;= 104&nbsp;<\/p>\n\n\n\n<p>104 + 11<sup>2<\/sup>&nbsp;= 225&nbsp;<\/p>\n\n\n\n<p>225 + 13<sup>2<\/sup>&nbsp;= 394&nbsp;<\/p>\n\n\n\n<p>394 + 17<sup>2<\/sup>&nbsp;= 683&nbsp;<\/p>\n\n\n\n<p>683 + 19<sup>2<\/sup>&nbsp;= 1044&nbsp;<\/p>\n\n\n\n<p>1044 + 23<sup>2&nbsp;<\/sup>= 1573&nbsp;<\/p>\n\n\n\n<p>1573 + 29<sup>2<\/sup>&nbsp;= 2414&nbsp;<\/p>\n\n\n\n<p>So, the series is 17, 21, 30, 55, 104, 225, 394, 683, 1044, 1573 and 2414.&nbsp;<\/p>\n\n\n\n<p>2414 is the eleventh term, so the value of n = 11&nbsp;<\/p>\n\n\n\n<p>Hence, option e.&nbsp;<\/p>\n\n\n\n<p>Q3.)&nbsp;The following numbers form a series. One of the numbers in the given series is odd one out. Find the odd number in the series and form a series with same pattern&nbsp;starting with the odd number and then find the sixth number in the new series formed.&nbsp;<\/p>\n\n\n\n<p>121, 277, 487, 757, 1101, 1521&nbsp;<\/p>\n\n\n\n<p>a.)&nbsp;[1101, 1197]&nbsp;<\/p>\n\n\n\n<p>b.)&nbsp;[757, 1617]&nbsp;<\/p>\n\n\n\n<p>c.)&nbsp;[1101, 2845]&nbsp;<\/p>\n\n\n\n<p>d.)&nbsp;[1521, 3685]&nbsp;<\/p>\n\n\n\n<p>e.)&nbsp;[757, 2157]&nbsp;<\/p>\n\n\n\n<p><strong>Answer:&nbsp;e)<\/strong>&nbsp;<\/p>\n\n\n\n<p><strong>Solution:<\/strong>&nbsp;<\/p>\n\n\n\n<p>We are adding multiple of consecutive natural numbers starting with 12&nbsp;<\/p>\n\n\n\n<p>121 + 12 \u00d7 13 = 277&nbsp;<\/p>\n\n\n\n<p>277 + 14 \u00d7 15 = 487&nbsp;<\/p>\n\n\n\n<p><strong>487 + 16 \u00d7 17 = 759<\/strong>&nbsp;<\/p>\n\n\n\n<p>759 + 18 \u00d7 19 = 1101&nbsp;<\/p>\n\n\n\n<p>1101 + 20 \u00d7 21 = 1521&nbsp;<\/p>\n\n\n\n<p>So, odd number is 757.&nbsp;<\/p>\n\n\n\n<p>Starting series with 757 we get sixth number as:&nbsp;<\/p>\n\n\n\n<p>757 + 12 \u00d7 13 = 913&nbsp;<\/p>\n\n\n\n<p>913 + 14 \u00d7 15 = 1123&nbsp;<\/p>\n\n\n\n<p>1123 + 16 \u00d7 17 = 1395&nbsp;<\/p>\n\n\n\n<p>1395 + 18 \u00d7 19 = 1737&nbsp;<\/p>\n\n\n\n<p>1737 + 20 \u00d7 21 = 2157&nbsp;<\/p>\n\n\n\n<p>Hence, option e.&nbsp;<\/p>\n\n\n\n<p>Q4.)&nbsp;A series is 121, 130, 155, 204, 285, 406.&nbsp;<\/p>\n\n\n\n<p>If another series __, 83, __, m, __, __ follows the same pattern as the given number series, then find the value of m.&nbsp;<\/p>\n\n\n\n<p>a.)&nbsp;161&nbsp;<\/p>\n\n\n\n<p>b.)&nbsp;157&nbsp;<\/p>\n\n\n\n<p>c.)&nbsp;238&nbsp;<\/p>\n\n\n\n<p>d.)&nbsp;108&nbsp;<\/p>\n\n\n\n<p>e.)&nbsp;150&nbsp;<\/p>\n\n\n\n<p><strong>Answer:&nbsp;b)<\/strong>&nbsp;<\/p>\n\n\n\n<p><strong>Solution:<\/strong>&nbsp;<\/p>\n\n\n\n<p>121 + 3<sup>2<\/sup>&nbsp;= 130&nbsp;<\/p>\n\n\n\n<p>130 + 5<sup>2<\/sup>&nbsp;= 155&nbsp;<\/p>\n\n\n\n<p>155 + 7<sup>2<\/sup>&nbsp;= 204&nbsp;<\/p>\n\n\n\n<p>204 + 9<sup>2<\/sup>&nbsp;= 285&nbsp;<\/p>\n\n\n\n<p>285 + 11<sup>2<\/sup>&nbsp;= 406&nbsp;<\/p>\n\n\n\n<p>Now,&nbsp;<\/p>\n\n\n\n<p>74 + 3<sup>2<\/sup>&nbsp;= 83&nbsp;<\/p>\n\n\n\n<p>83 + 5<sup>2<\/sup>&nbsp;= 108&nbsp;<\/p>\n\n\n\n<p>108 + 7<sup>2<\/sup>&nbsp;= 157&nbsp;<\/p>\n\n\n\n<p>157 + 9<sup>2<\/sup>&nbsp;= 238&nbsp;<\/p>\n\n\n\n<p>238 + 11<sup>2<\/sup>&nbsp;= 359&nbsp;<\/p>\n\n\n\n<p>Hence, option b.&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image\"><a href=\"https:\/\/www.practicemock.com\/exams\/banking\/sbi-po\/?refcode=2918&amp;utm_source=Blog_Number+Series+for+SBI+PO+with+Q%26A_191021_SBIPM&amp;utm_medium=Link&amp;utm_campaign=SBIPM\"><img decoding=\"async\" src=\"https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2021\/09\/SBI_PO_270821-1024x128.jpg\" alt=\"Number Series for SBI PO \"\/><\/a><\/figure>\n\n\n\n<p>Q5.)&nbsp;The following numbers form a series. Find the odd one out.&nbsp;<\/p>\n\n\n\n<p>28, 72, 154, 280, 468, 728&nbsp;<\/p>\n\n\n\n<p>a.)&nbsp;72&nbsp;<\/p>\n\n\n\n<p>b.)&nbsp;154&nbsp;<\/p>\n\n\n\n<p>c.)&nbsp;280&nbsp;<\/p>\n\n\n\n<p>d.)&nbsp;468&nbsp;<\/p>\n\n\n\n<p>e.)&nbsp;728&nbsp;<\/p>\n\n\n\n<p><strong>Answer:&nbsp;b)<\/strong>&nbsp;<\/p>\n\n\n\n<p><strong>Solution:<\/strong>&nbsp;<\/p>\n\n\n\n<p>The series follows the pattern:&nbsp;<\/p>\n\n\n\n<p>1<sup>3<\/sup>&nbsp;+ 3<sup>3<\/sup>&nbsp;= 28,&nbsp;<\/p>\n\n\n\n<p>2<sup>3<\/sup>&nbsp;+ 4<sup>3<\/sup>&nbsp;= 72,&nbsp;<\/p>\n\n\n\n<p><strong>3<\/strong><strong><sup>3<\/sup><\/strong><strong>&nbsp;+ 5<\/strong><strong><sup>3<\/sup><\/strong><strong>&nbsp;= 152,&nbsp;<\/strong>&nbsp;<\/p>\n\n\n\n<p>4<sup>3<\/sup>&nbsp;+ 6<sup>3<\/sup>&nbsp;= 280,&nbsp;<\/p>\n\n\n\n<p>5<sup>3<\/sup>&nbsp;+ 7<sup>3<\/sup>&nbsp;= 468,&nbsp;<\/p>\n\n\n\n<p>6<sup>3<\/sup>&nbsp;+ 8<sup>3<\/sup>&nbsp;= 728&nbsp;<\/p>\n\n\n\n<p>Therefore, 152 should be in place of 154.&nbsp;<\/p>\n\n\n\n<p>Hence, option b.&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image\"><a href=\"https:\/\/www.practicemock.com\/exams\/banking\/sbi-po\/?refcode=2918&amp;utm_source=Blog_Number+Series+for+SBI+PO+with+Q%26A_191021_SBIPM&amp;utm_medium=Link&amp;utm_campaign=SBIPM\"><img decoding=\"async\" src=\"https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2021\/09\/SBI_PO_270821-1024x128.jpg\" alt=\"SBI_PO_Free Mock\"\/><\/a><\/figure>\n\n\n\n<p>Find daily SBI PO 2021 updates posted on our official&nbsp;<a href=\"https:\/\/instagram.com\/practicemock?utm_medium=copy_link\" target=\"_blank\" rel=\"noreferrer noopener\">Instagram handle&nbsp;<\/a>as well.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p>You might want to subscribe to our push notifications for such daily valuable articles.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p>Still, have some doubts about what we discussed in this blog? Then, leave your queries in the comment section below. We will surely respond to them.&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The Number Series for SBI PO has a good level of questions which should be practiced with due diligence. Read the article for such questions.<\/p>\n","protected":false},"author":5,"featured_media":9894,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_uag_custom_page_level_css":"","_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_uf_show_specific_survey":0,"_uf_disable_surveys":false,"footnotes":""},"categories":[49],"tags":[1064,240,1027],"class_list":["post-9889","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-sbi-po","tag-sbi-po-number-series","tag-sbi-po-prelims-exam-preparation","tag-sbi-po-quantitative-aptitude"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v25.9 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Number Series for SBI PO with Q&amp;A - Practicemock<\/title>\n<meta name=\"description\" content=\"The Number Series for SBI PO has a good level of questions which should be practiced with due diligence. 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