{"id":80793,"date":"2024-03-08T12:17:43","date_gmt":"2024-03-08T06:47:43","guid":{"rendered":"https:\/\/www.practicemock.com\/blog\/?p=80793"},"modified":"2025-11-25T18:02:47","modified_gmt":"2025-11-25T12:32:47","slug":"quantitative-aptitude-prep-plan-important-question-for-rbi-grade-b","status":"publish","type":"post","link":"https:\/\/www.practicemock.com\/blog\/quantitative-aptitude-prep-plan-important-question-for-rbi-grade-b\/","title":{"rendered":"Quantitative Aptitude Prep Plan + Important Question for RBI Grade B 2024"},"content":{"rendered":"\n

Quantitative Aptitude Preparation Strategy 2024:<\/strong> Preparing for the Quantitative Aptitude section of the RBI Grade B 2024 exam requires a strategic approach to tackle the diverse range of mathematical concepts and problem-solving skills tested. This article aims to provide a comprehensive guide to crafting an effective preparation strategy, along with important questions tailored for the RBI Grade B exam.<\/p>\n\n\n\n

Kickstart your preparation with a FREE RBI Grade B 2024 Mock Test<\/a>\ud83d\udc48\ud83c\udfc6<\/h3>\n\n\n\n

Also Read: RBI Grade B 2024 Notification Details<\/a> <\/h3>\n\n\n\n

<\/p>\n\n\n\n

Quantitative Aptitude Preparation Strategy 2024<\/h2>\n\n\n\n

Understand the Syllabus:<\/strong> Begin by familiarizing yourself with the Quantitative Aptitude syllabus for RBI Grade B 2024. Identify your strengths and weaknesses in each topic to prioritize your preparation accordingly.<\/p>\n\n\n\n

Conceptual Clarity:<\/strong> Focus on building a strong foundation in fundamental mathematical concepts. Understand the underlying principles and formulas associated with each topic to solve problems effectively.<\/p>\n\n\n\n

Practice Regularly:<\/strong> Practice is key to mastering Quantitative Aptitude. Solve a variety of questions from different difficulty levels to enhance your problem-solving skills and speed.<\/p>\n\n\n\n

Time Management:<\/strong> Time management is crucial during the exam. Practice solving questions within the stipulated time frame to improve your speed and accuracy.<\/p>\n\n\n\n

Mock Tests and Previous Year Papers: <\/strong>Take regular mock tests and solve previous year question papers to familiarize yourself with the exam pattern and assess your preparation level. Analyze your performance and identify areas for improvement.<\/p>\n\n\n\n

Signup for a Free Grade B 2024 Mock Test & Improve Your Performance 10X<\/a>\ud83d\ude80<\/h2>\n\n\n\n

Quantitative Aptitude Preparation Strategy + Important Question for RBI Grade B<\/h2>\n\n\n\n

Now, let’s delve into some important questions for the Quantitative Aptitude section of RBI Grade B 2024:<\/p>\n\n\n\n

Question 1:<\/strong> One year hence from now, the ratio of ages of \u2018J\u2019 and \u2018K will be 9:10, respectively. One year ago from now, the ratio of ages of \u2018K\u2019 and \u2018M\u2019 was 4:5, respectively. The sum of the present ages of \u2018K and \u2018M\u2019 is 110 years. What was the ratio of ages of \u2018K\u2019 and \u2018M\u2019, respectively when the youngest among the three was 19 years old?<\/p>\n\n\n\n

A) 1:2<\/p>\n\n\n\n

B) 3:4<\/p>\n\n\n\n

C) 3:5<\/p>\n\n\n\n

D) 2:3<\/p>\n\n\n\n

E) 4:7<\/p>\n\n\n\n

Question 2:<\/strong> \u2018A\u2019 alone working at 75% of her full efficiency can finish a work in 24 days. \u2018A\u2019 and \u2018B\u2019 working together with full efficiency can complete the same work in 10.8 days. If \u2018A\u2019 alone starts the work, works on it for \u2018t\u2019 days then leaves, then the remaining work is completed by \u2018B\u2019 alone in (t \u2013 8) days. What is the value of \u2018t\u2019?<\/p>\n\n\n\n

A) 14<\/p>\n\n\n\n

B) 16<\/p>\n\n\n\n

C) 12<\/p>\n\n\n\n

D) 15<\/p>\n\n\n\n

E) 18<\/p>\n\n\n\n

Signup for a Free Grade B 2024 Mock Test & Improve Your Performance 10X<\/a>\ud83d\ude80<\/h2>\n\n\n\n

Question 3:<\/strong> 13 years ago from now, \u2018P\u2019 was twice as old as \u2018Q\u2019. If __ years hence from now, the ratio of age of \u2018P\u2019 and \u2018Q\u2019 will be 25:19, respectively, then present age of \u2018Q\u2019 is __ years.<\/p>\n\n\n\n

The values given in which of the following options will fill the blanks in the same order in which is it given to make the statement true:<\/p>\n\n\n\n

I. 15, 28<\/p>\n\n\n\n

II. 13, 25<\/p>\n\n\n\n

III. 17, 34<\/p>\n\n\n\n

A) Only I<\/p>\n\n\n\n

B) Only III<\/p>\n\n\n\n

C) Only II and III<\/p>\n\n\n\n

D) All I, II and III<\/p>\n\n\n\n

E) Only II<\/p>\n\n\n\n

Question 4:<\/strong> The cost of booking a hotel is partially fixed (irrespective of number of people) and partially variable. When the hotel is booked for 25 people the average cost per person is Rs. 300. However, when the hotel is booked for 80 people the average cost per person is Rs. 162.5. Mr. \u2018A\u2019 wants to book the room for 100 people, what is the average cost (in Rs.) per person that he needs to pay?<\/p>\n\n\n\n

A) 196<\/p>\n\n\n\n

B) 150<\/p>\n\n\n\n

C) 200<\/p>\n\n\n\n

D) 120<\/p>\n\n\n\n

E) 210<\/p>\n\n\n\n

Question 5:<\/strong> A bottle in the form of a cylinder whose lid is also in the form of a cylinder. The radius of the base of the bottle is 10.5 cm and the height of the bottle below the lid is 21 cm. If the radius of the lid and the base of the bottle are same and the total curved surface area of the whole bottle (bottle + lid) is 1584 cm2<\/sup>, then find the height of the lid of the bottle.<\/p>\n\n\n\n

A) 10 cm<\/p>\n\n\n\n

B) 7 cm<\/p>\n\n\n\n

C) 6 cm<\/p>\n\n\n\n

D) 4 cm<\/p>\n\n\n\n

E) 3 cm<\/p>\n\n\n\n

Question 6:<\/strong> \u2018p\u2019 and \u2018q\u2019 are roots of the equation x2<\/sup> + Bx + 400 = 0. If \u2018p\u2019 and \u2018q\u2019 are real and equal, then find the value of \u2018B\u2019?<\/p>\n\n\n\n

A) 40<\/p>\n\n\n\n

B) 30<\/p>\n\n\n\n

C) 20<\/p>\n\n\n\n

D) 50<\/p>\n\n\n\n

E) None of these<\/p>\n\n\n\n

Signup for a Free Grade B 2024 Mock Test & Improve Your Performance 10X<\/a>\ud83d\ude80<\/h2>\n\n\n\n

Question 7:<\/strong> \u2018p\u2019 and \u2018q\u2019 are roots of the equation x2<\/sup> + Bx + 400. If \u2018p\u2019 and \u2018q\u2019 are real and equal, then find the roots of the equation x2<\/sup> \u2013 (B + 5)x + 500 = 0 given that both roots of this equation are also real.<\/p>\n\n\n\n

A) 5, 100<\/p>\n\n\n\n

B) 30, 35<\/p>\n\n\n\n

C) 25, 30<\/p>\n\n\n\n

D) 20, 25<\/p>\n\n\n\n

E) 50, 10<\/p>\n\n\n\n

Question 8:<\/strong> In the given table there are two columns I and II. Column I contains three equations and column II contains the roots of the equations given in column I, not necessarily in the same order. Study the given table carefully and answer the questions accordingly.<\/p>\n\n\n\n

Column I<\/td>Column II<\/td><\/tr>
I. x2<\/sup> \u2013 3x = 28<\/td>a.) (8,13)<\/td><\/tr>
II. y2 <\/sup>+ 104 = 21y<\/td>b.) (-4, 8)<\/td><\/tr>
III. z2 <\/sup>= 4z + 32<\/td>c.) (7, -4)<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

Which of the following relation is correct?<\/p>\n\n\n\n

A) I – a, II – b, III – c<\/p>\n\n\n\n

B) I – a, II – c, III – b<\/p>\n\n\n\n

C) I – c, II – b, III – a<\/p>\n\n\n\n

D) I – c, II – a, III – b<\/p>\n\n\n\n

E) I – b, II – a, III – c<\/p>\n\n\n\n

Question 9:<\/strong> Two series I and II following a certain pattern are given below. Determine the value of \u2018x\u2019 in series \u2018I\u2019 and then find the number that will come in place of \u2018?\u2019 in series II.<\/p>\n\n\n\n

I. 465, 930, 310, 1240, x, 1488<\/p>\n\n\n\n

II. 180, ?, 146, x, 112, 282<\/p>\n\n\n\n

A) 196<\/p>\n\n\n\n

B) 256<\/p>\n\n\n\n

C) 214<\/p>\n\n\n\n

D) 228<\/p>\n\n\n\n

E) 218<\/p>\n\n\n\n

Question 10:<\/strong> Given below are three series: I, II and III. Each of the given series consist an odd one out number. The odd one out number in series I, II and III are represented by \u2018P\u2019, \u2018Q\u2019 and \u2018R\u2019, respectively. You have to find the values of \u2018P\u2019, \u2018Q\u2019 and \u2018R\u2019 and establish the correct relation among them.I. 20, 32, 62, 92, 140, 200II. 14, 21, 42, 110, 315, 1102.5III. 124, 107, 90, 73, 56, 42<\/p>\n\n\n\n

A) P > Q < R<\/p>\n\n\n\n

B) P < Q > R<\/p>\n\n\n\n

C) P > Q > R<\/p>\n\n\n\n

D) P = Q > R<\/p>\n\n\n\n

E) P > Q = R<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 1:<\/strong> None<\/p>\n\n\n\n

A) 1:2<\/p>\n\n\n\n

B) 3:4<\/p>\n\n\n\n

C) 3:5<\/p>\n\n\n\n

D) 2:3<\/p>\n\n\n\n

E) 4:7<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 2:<\/strong> None<\/p>\n\n\n\n

A) 14<\/p>\n\n\n\n

B) 16<\/p>\n\n\n\n

C) 12<\/p>\n\n\n\n

D) 15<\/p>\n\n\n\n

E) 18<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 3:<\/strong> None<\/p>\n\n\n\n

A) Only I<\/p>\n\n\n\n

B) Only III<\/p>\n\n\n\n

C) Only II and III<\/p>\n\n\n\n

D) All I, II and III<\/p>\n\n\n\n

E) Only II<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 4:<\/strong> None<\/p>\n\n\n\n

A) 196<\/p>\n\n\n\n

B) 150<\/p>\n\n\n\n

C) 200<\/p>\n\n\n\n

D) 120<\/p>\n\n\n\n

E) 210<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 5:<\/strong> \u092c\u0947\u0932\u0928 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u090f\u0915 \u092c\u094b\u0924\u0932 \u0915\u093e \u0922\u0915\u094d\u0915\u0928 \u092d\u0940 \u092c\u0947\u0932\u0928 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0939\u094b\u0924\u093e \u0939\u0948\u0964 \u092c\u094b\u0924\u0932 \u0915\u0947 \u0906\u0927\u093e\u0930 \u0915\u0940 \u0924\u094d\u0930\u093f\u091c\u094d\u092f\u093e 10.5 cm \u0939\u0948 \u0914\u0930 \u0922\u0915\u094d\u0915\u0928 \u0915\u0947 \u0928\u0940\u091a\u0947 \u0915\u0940 \u092c\u094b\u0924\u0932 \u0915\u0940 \u090a\u0902\u091a\u093e\u0908 21 cm \u0939\u0948\u0964 \u092f\u0926\u093f \u0922\u0915\u094d\u0915\u0928 \u0915\u0940 \u0924\u094d\u0930\u093f\u091c\u094d\u092f\u093e \u0914\u0930 \u092c\u094b\u0924\u0932 \u0915\u093e \u0906\u0927\u093e\u0930 \u0938\u092e\u093e\u0928 \u0939\u0948 \u0914\u0930 \u092a\u0942\u0930\u0940 \u092c\u094b\u0924\u0932 (\u092c\u094b\u0924\u0932 + \u0922\u0915\u094d\u0915\u0928) \u0915\u093e \u0915\u0941\u0932 \u0935\u0915\u094d\u0930 \u092a\u0943\u0937\u094d\u0920\u0940\u092f \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932 1584 m2<\/sup> \u0939\u0948, \u0924\u094b \u092c\u094b\u0924\u0932 \u0915\u0947 \u0922\u0915\u094d\u0915\u0928 \u0915\u0940 \u090a\u0902\u091a\u093e\u0908 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947\u0902\u0964<\/p>\n\n\n\n

A) 10 cm<\/p>\n\n\n\n

B) 7 cm<\/p>\n\n\n\n

C) 6 cm<\/p>\n\n\n\n

D) 4 cm<\/p>\n\n\n\n

E) 3 cm<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 6:<\/strong> ‘p’ \u0914\u0930 ‘q’ \u0938\u092e\u0940\u0915\u0930\u0923 x2<\/sup> + Bx + 400 = 0 \u0915\u0947 \u0938\u0942\u0924\u094d\u0930 \u0939\u0948\u0902\u0964 \u092f\u0926\u093f ‘p’ \u0914\u0930 ‘q’ \u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 \u0914\u0930 \u0938\u092e\u093e\u0928 \u0939\u0948\u0902, \u0924\u094b ‘B’ \u0915\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947\u0902?<\/p>\n\n\n\n

A) 40<\/p>\n\n\n\n

B) 30<\/p>\n\n\n\n

C) 20<\/p>\n\n\n\n

D) 50<\/p>\n\n\n\n

E) \u0907\u0928\u092e\u0947\u0902 \u0938\u0947 \u0915\u094b\u0908 \u0928\u0939\u0940\u0902<\/p>\n\n\n\n

Signup for a Free Grade B 2024 Mock Test & Improve Your Performance 10X<\/a>\ud83d\ude80<\/h2>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 7:<\/strong> ‘p’ \u0914\u0930 ‘q’ \u0938\u092e\u0940\u0915\u0930\u0923 x2<\/sup> + Bx + 400 \u0915\u0947 \u0938\u093f\u0924\u094d\u0930 \u0939\u0948\u0902\u0964 \u092f\u0926\u093f ‘p’ \u0914\u0930 ‘q’ \u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 \u0914\u0930 \u0938\u092e\u093e\u0928 \u0939\u0948\u0902, \u0924\u094b \u0938\u092e\u0940\u0915\u0930\u0923 x2<\/sup> – (B + 5)x + 500 = 0 \u0915\u0947 \u0938\u0942\u0924\u094d\u0930 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947\u0902\u0964 \u0926\u093f\u092f\u093e \u0939\u0948 \u0915\u093f \u0907\u0938 \u0938\u092e\u0940\u0915\u0930\u0923 \u0915\u0947 \u0926\u094b\u0928\u094b\u0902 \u0938\u0942\u0924\u094d\u0930 \u092d\u0940 \u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 (real) \u0939\u0948\u0902\u0964<\/p>\n\n\n\n

A) 5, 100<\/p>\n\n\n\n

B) 30, 35<\/p>\n\n\n\n

C) 25, 30<\/p>\n\n\n\n

D) 20, 25<\/p>\n\n\n\n

E) 50, 10<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 8:<\/strong> \u0926\u0940 \u0917\u0908 \u0924\u093e\u0932\u093f\u0915\u093e \u092e\u0947\u0902 \u0926\u094b \u0915\u0949\u0932\u092e I \u0914\u0930 II \u0939\u0948\u0902\u0964 \u0915\u0949\u0932\u092e I \u092e\u0947\u0902 \u0924\u0940\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948\u0902 \u0914\u0930 \u0915\u0949\u0932\u092e II \u092e\u0947\u0902 \u0915\u0949\u0932\u092e I \u092e\u0947\u0902 \u0926\u093f\u090f \u0917\u090f \u0938\u092e\u0940\u0915\u0930\u0923\u094b\u0902 \u0915\u0947 \u0938\u0942\u0924\u094d\u0930 \u0939\u0948\u0902, \u091c\u093c\u0930\u0942\u0930\u0940 \u0928\u0939\u0940\u0902 \u0915\u093f \u0907\u0938\u0940 \u0915\u094d\u0930\u092e \u092e\u0947\u0902 \u0939\u094b\u0902\u0964 \u0926\u0940 \u0917\u0908 \u0924\u093e\u0932\u093f\u0915\u093e \u0915\u093e \u0927\u094d\u092f\u093e\u0928\u092a\u0942\u0930\u094d\u0935\u0915 \u0905\u0927\u094d\u092f\u092f\u0928 \u0915\u0930\u0947\u0902 \u0914\u0930 \u0909\u0938\u0915\u0947 \u0905\u0928\u0941\u0938\u093e\u0930 \u092a\u094d\u0930\u0936\u094d\u0928\u094b\u0902 \u0915\u0947 \u0909\u0924\u094d\u0924\u0930 \u0926\u0947\u0902\u0964<\/p>\n\n\n\n

Column I<\/td>Column II<\/td><\/tr>
I. x2<\/sup> \u2013 3x = 28<\/td>a.) (8,13)<\/td><\/tr>
II. y2 <\/sup>+ 104 = 21y<\/td>b.) (-4, 8)<\/td><\/tr>
III. z2 <\/sup>= 4z + 32<\/td>c.) (7, -4)<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0938\u0947 \u0915\u094c\u0928 \u0938\u093e \u0938\u0902\u092c\u0902\u0927 \u0938\u0939\u0940 \u0939\u0948?<\/p>\n\n\n\n

A) I – a, II – b, III – c<\/p>\n\n\n\n

B) I – a, II – c, III – b<\/p>\n\n\n\n

C) I – c, II – b, III – a<\/p>\n\n\n\n

D) I – c, II – a, III – b<\/p>\n\n\n\n

E) I – b, II – a, III – c<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 9:<\/strong> \u090f\u0915 \u0928\u093f\u0936\u094d\u091a\u093f\u0924 \u092a\u0948\u091f\u0930\u094d\u0928 \u0915\u093e \u0905\u0928\u0941\u0938\u0930\u0923 \u0915\u0930\u0924\u0947 \u0939\u0941\u090f \u0926\u094b \u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e I \u0914\u0930 II \u0928\u0940\u091a\u0947 \u0926\u0940 \u0917\u0908 \u0939\u0948\u0902\u0964 \u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e ‘I’ \u092e\u0947\u0902 ‘x’ \u0915\u093e \u092e\u093e\u0928 \u0928\u093f\u0930\u094d\u0927\u093e\u0930\u093f\u0924 \u0915\u0930\u0947\u0902 \u0914\u0930 \u092b\u093f\u0930 \u0935\u0939 \u0938\u0902\u0916\u094d\u092f\u093e \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947\u0902 \u091c\u094b \u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e II \u092e\u0947\u0902 ‘?’ \u0915\u0947 \u0938\u094d\u0925\u093e\u0928 \u092a\u0930 \u0906\u090f\u0917\u0940\u0964<\/p>\n\n\n\n

I. 465, 930, 310, 1240, x, 1488<\/p>\n\n\n\n

II. 180, ?, 146, x, 112, 282<\/p>\n\n\n\n

A) 196<\/p>\n\n\n\n

B) 256<\/p>\n\n\n\n

C) 214<\/p>\n\n\n\n

D) 228<\/p>\n\n\n\n

E) 218<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 10:<\/strong> \u0928\u0940\u091a\u0947 \u0924\u0940\u0928 \u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e\u090f\u0901 : I, II \u0914\u0930 III \u0926\u0940 \u0917\u0908 \u0939\u0948\u0902\u0964 \u0926\u0940 \u0917\u0908 \u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e \u092e\u0947\u0902 \u0938\u0947 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u092e\u0947\u0902 \u090f\u0915 \u0935\u093f\u0937\u092e \u0938\u0902\u0916\u094d\u092f\u093e \u0939\u0948\u0964 \u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e I, II \u0914\u0930 III \u092e\u0947\u0902 \u0935\u093f\u0937\u092e \u090f\u0915 \u0938\u0902\u0916\u094d\u092f\u093e \u0915\u094b \u0915\u094d\u0930\u092e\u0936\u0903 ‘P’, ‘Q’ \u0914\u0930 ‘R’ \u0926\u094d\u0935\u093e\u0930\u093e \u0926\u0930\u094d\u0936\u093e\u092f\u093e \u091c\u093e\u0924\u093e \u0939\u0948\u0964 \u0906\u092a\u0915\u094b ‘P’, ‘Q’ \u0914\u0930 ‘R’ \u0915\u0947 \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0928\u0947 \u0939\u0948\u0902 \u0914\u0930 \u0909\u0928\u092e\u0947\u0902 \u0938\u0939\u0940 \u0938\u0902\u092c\u0902\u0927 \u0938\u094d\u0925\u093e\u092a\u093f\u0924 \u0915\u0930\u0928\u093e \u0939\u0948\u0964<\/p>\n\n\n\n

I. 20, 32, 62, 92, 140, 200<\/p>\n\n\n\n

II. 14, 21, 42, 110, 315, 1102.5<\/p>\n\n\n\n

III. 124, 107, 90, 73, 56, 42<\/p>\n\n\n\n

A) P > Q < R<\/p>\n\n\n\n

B) P < Q > R<\/p>\n\n\n\n

C) P > Q > R<\/p>\n\n\n\n

D) P = Q > R<\/p>\n\n\n\n

E) P > Q = R<\/p>\n\n\n\n

 ANSWER KEYS and SOLUTIONS:<\/h2>\n\n\n\n
1) – D)<\/td>2) – A)<\/td>3) – E)<\/td>4) – B)<\/td>5) – E)<\/td>6) – E)<\/td><\/tr>
7) – D)<\/td>8) – D)<\/td>9) – C)<\/td>10) – B)<\/td><\/td><\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

Solution 1: D)<\/strong><\/p>\n\n\n\n

1 year hence from now, let the age of \u2018J\u2019 will be \u20189x\u2019 years<\/p>\n\n\n\n

So, present age of \u2018J\u2019 = (9x \u2013 1) years<\/p>\n\n\n\n

1 year hence from now, age of \u2018K\u2019 = 9x \u00d7 (10\/9) = \u201810x\u2019 years<\/p>\n\n\n\n

So, present age of \u2018K\u2019 = (10x \u2013 1) years<\/p>\n\n\n\n

1 year ago, age of \u2018K\u2019 = (10x \u2013 2) years<\/p>\n\n\n\n

So, 1 year ago, age of \u2018M\u2019 = (10x \u2013 2) \u00d7 (5\/4) = (12.5x \u2013 2.5) years<\/p>\n\n\n\n

So, present age of \u2018M\u2019 = 12.5x \u2013 2.5 + 1 = (12.5x \u2013 1.5) years<\/p>\n\n\n\n

Sum of present ages of \u2018K\u2019 and \u2018M = (10x \u2013 1) + (12.5x \u2013 1.5) = {22.5x \u2013 2.5} years<\/p>\n\n\n\n

ATQ;<\/p>\n\n\n\n

22.5x \u2013 2.5 = 110<\/p>\n\n\n\n

Or, 22.5x = 110 + 2.5 = 112.5<\/p>\n\n\n\n

Or, x = 112.5 \u00f7 22.5 = 5<\/p>\n\n\n\n

So, present ages of \u2018J\u2019, \u2018K\u2019 and \u2018M\u2019 is 44 (9 \u00d7 5 \u2013 1) years, 49 (10 \u00d7 5 \u2013 1) years and 61 (12.5 \u00d7 5 \u2013 1.5) years, respectively.<\/p>\n\n\n\n

So, the youngest person is \u2018J\u2019.<\/p>\n\n\n\n

Number of years before when \u2018J\u2019 was 19 years old = 44 \u2013 19 = 25 years<\/p>\n\n\n\n

So, ratio of ages of \u2018K\u2019 and \u2018M\u2019 25 years ago = (49 \u2013 25):(61 \u2013 25) = 24:36 = 2:3<\/p>\n\n\n\n

Hence, option d.<\/p>\n\n\n\n

Solution 2: A)<\/strong><\/p>\n\n\n\n

Time taken by \u2018A\u2019 alone complete the work in full efficiency = 24 \u00d7 0.75 = 18 days<\/p>\n\n\n\n

Let the total work = 54 units<\/p>\n\n\n\n

Then, efficiency of \u2018A\u2019 alone = (54\/18) = 3 units\/day<\/p>\n\n\n\n

Combined efficiency of \u2018A\u2019 and \u2018B\u2019 = (54\/10.8) = 5 units\/day<\/p>\n\n\n\n

So, efficiency of \u2018B\u2019 alone = 5 \u2013 3 = 2 units\/day<\/p>\n\n\n\n

According to the question,<\/p>\n\n\n\n

3 \u00d7 t + 2 \u00d7 (t \u2013 8) = 54<\/p>\n\n\n\n

Or, 3t + 2t \u2013 16 = 54<\/p>\n\n\n\n

Or, 5t = 54 + 16 = 70<\/p>\n\n\n\n

Or, t = (70\/5) = 14<\/p>\n\n\n\n

Hence, option a.<\/p>\n\n\n\n

Signup for a Free Grade B 2024 Mock Test & Improve Your Performance 10X<\/a>\ud83d\ude80<\/h2>\n\n\n\n

Solution 3: E)<\/strong><\/p>\n\n\n\n

Let present ages of \u2018P\u2019 and \u2018Q\u2019 be \u2018a\u2019 years and \u2018b\u2019 years, respectively.<\/p>\n\n\n\n

Therefore, a \u2013 13 = 2 \u00d7 (b \u2013 13)<\/p>\n\n\n\n

Or, a \u2013 13 = 2b \u2013 26<\/p>\n\n\n\n

Or, a = 2b \u2013 13\u2026\u2026\u2026\u2026\u2026. (1)<\/p>\n\n\n\n

For I:<\/p>\n\n\n\n

{(a + 15)\/(b + 15)} = 25\/19<\/p>\n\n\n\n

Or, 19 \u00d7 (a + 15) = 25 \u00d7 (b + 15)<\/p>\n\n\n\n

Or, 19a + 285 = 25b + 375<\/p>\n\n\n\n

19a \u2013 25b = 90\u2026\u2026\u2026\u2026\u2026 (2)<\/p>\n\n\n\n

Putting value of \u2018a\u2019 in equation (2)<\/p>\n\n\n\n

19 \u00d7 (2b \u2013 13) \u2013 25b = 90<\/p>\n\n\n\n

Or, 38b \u2013 247 \u2013 25b = 90<\/p>\n\n\n\n

Or, 13b = 337<\/p>\n\n\n\n

Or, b ~ 25.92<\/p>\n\n\n\n

Therefore, present age of \u2018Q\u2019 = 25.92 years<\/p>\n\n\n\n

Hence, I is false.<\/p>\n\n\n\n

For II:<\/p>\n\n\n\n

{(a + 13)\/(b + 13)} = 25\/19<\/p>\n\n\n\n

Or, 19 \u00d7 (a + 13) = 25 \u00d7 (b + 13)<\/p>\n\n\n\n

Or, 19a + 247 = 25b + 325<\/p>\n\n\n\n

Or, 19a \u2013 25b = 78\u2026\u2026\u2026\u2026… (3)<\/p>\n\n\n\n

Putting value of \u2018a\u2019 in equation (3)<\/p>\n\n\n\n

19 \u00d7 (2b \u2013 13) \u2013 25b = 78<\/p>\n\n\n\n

Or, 38b \u2013 247 \u2013 25b = 78<\/p>\n\n\n\n

Or, 13b = 325<\/p>\n\n\n\n

Or, b = 25<\/p>\n\n\n\n

Therefore, present age of \u2018Q\u2019 = 25 years<\/p>\n\n\n\n

Therefore, II is true.<\/p>\n\n\n\n

For III:<\/p>\n\n\n\n

(a + 17)\/(b + 17) = 25\/19<\/p>\n\n\n\n

Or, 19(a + 17) = 25(b + 17)<\/p>\n\n\n\n

Or, 19a + 323 = 25b + 425<\/p>\n\n\n\n

19a \u2013 25b = 102\u2026\u2026\u2026\u2026 (4)<\/p>\n\n\n\n

Putting value of \u2018a\u2019 in equation (4)<\/p>\n\n\n\n

19 \u00d7 (2b \u2013 13) \u2013 25b = 102<\/p>\n\n\n\n

Or, 38b \u2013 247 \u2013 25b = 102<\/p>\n\n\n\n

Or, 13b = 349<\/p>\n\n\n\n

Or, b ~ 26.84<\/p>\n\n\n\n

Therefore, present age of \u2018Q\u2019 = 26.84 years<\/p>\n\n\n\n

Hence, III is false.<\/p>\n\n\n\n

Hence, option e.<\/p>\n\n\n\n

Signup for a Free Grade B 2024 Mock Test & Improve Your Performance 10X<\/a>\ud83d\ude80<\/h2>\n\n\n\n

Solution 4: B)<\/strong><\/p>\n\n\n\n

Total cost when the hotel is booked for 25 people = 25 \u00d7 300 = Rs. 7,500Total cost when the hotel is booked for 80 people = 80 \u00d7 162.5 = Rs. 13,000So, variable cost for extra 55 people i.e. (80 \u2013 25) = 13,000 \u2013 7500 = Rs. 5,500Therefore, variable cost per person is = 5500 \u00f7 55 = Rs. 100ATQ;25 \u00d7 100 + fixed cost = 7,500Or, fixed cost = Rs. 5,000So, total costs when booking the hotel for 100 people = 100 \u00d7 100 + 5000 = Rs. 15,000Required average = (15000\/100) = Rs. 150<\/p>\n\n\n\n

Hence, option b.<\/p>\n\n\n\n

Solution 5: E)<\/strong><\/p>\n\n\n\n

Let height of the lid is \u2018h\u2019 cm<\/p>\n\n\n\n

According to the question,<\/p>\n\n\n\n

2 \u00d7 (22\/7) \u00d7 (21\/2) \u00d7 (21 + h) = 1584<\/p>\n\n\n\n

Or, h = 3<\/p>\n\n\n\n

So, the height of the lid = 3 cm<\/p>\n\n\n\n

Hence, option e.<\/p>\n\n\n\n

Solution 6: E)<\/strong><\/p>\n\n\n\n

Since \u2018p\u2019 and \u2018q\u2019 are both real and equal,<\/p>\n\n\n\n

So, \u221a(B2<\/sup> \u2013 4AC) = 0<\/p>\n\n\n\n

So, \u221a(B2<\/sup> \u2013 4 \u00d7 400) = 0<\/p>\n\n\n\n

Or, B2<\/sup> = 1600<\/p>\n\n\n\n

So, B = \u00b140<\/p>\n\n\n\n

Hence, option e.<\/p>\n\n\n\n

Solution 7: D)<\/strong><\/p>\n\n\n\n

Since \u2018p\u2019 and \u2018q\u2019 are both real and equal.<\/p>\n\n\n\n

So, \u221a(B2<\/sup> \u2013 4AC) = 0<\/p>\n\n\n\n

So, \u221a(B2<\/sup> \u2013 4 \u00d7 400) = 0<\/p>\n\n\n\n

Or, B2<\/sup> = 1600<\/p>\n\n\n\n

So, B = \u00b140<\/p>\n\n\n\n

At B = 40, the given equation becomes, x2<\/sup> \u2013 45x + 500 = 0<\/p>\n\n\n\n

So, x2<\/sup> \u2013 25x \u2013 20x + 500 = 0<\/p>\n\n\n\n

Or, x(x \u2013 25) \u2013 20(x \u2013 25) = 0<\/p>\n\n\n\n

Or, (x \u2013 20)(x \u2013 25) = 0<\/p>\n\n\n\n

So, x = 20 or x = 25<\/p>\n\n\n\n

And, at B = -40, the given equation becomes x2<\/sup> \u2013 (-35x) + 500 = 0<\/p>\n\n\n\n

So, x2<\/sup> + 35x + 500 = 0<\/p>\n\n\n\n

Since, \u221a{352<\/sup> \u2013 (4 \u00d7 500)} is irrational, the roots of this equation are not real.<\/p>\n\n\n\n

So, required roots = 20 and 25.<\/p>\n\n\n\n

Hence, option d.<\/p>\n\n\n\n

Signup for a Free Grade B 2024 Mock Test & Improve Your Performance 10X<\/a>\ud83d\ude80<\/h2>\n\n\n\n

Solution 8: D)<\/strong><\/p>\n\n\n\n

From I:<\/p>\n\n\n\n

x2<\/sup> \u2013 3x = 28<\/p>\n\n\n\n

Or, x2<\/sup> \u2013 3x \u2013 28 = 0<\/p>\n\n\n\n

Or, x2<\/sup> \u2013 7x + 4x \u2013 28 = 0<\/p>\n\n\n\n

Or, x(x \u2013 7) + 4(x \u2013 7) = 0<\/p>\n\n\n\n

Or, (x \u2013 7)(x + 4) = 0<\/p>\n\n\n\n

So, x = 7 or x = -4<\/p>\n\n\n\n

From II:<\/p>\n\n\n\n

y2 <\/sup>+ 104 = 21y<\/p>\n\n\n\n

Or, y2<\/sup> \u2013 21y + 104 = 0<\/p>\n\n\n\n

Or, y2<\/sup> \u2013 13y \u2013 8y + 104 = 0<\/p>\n\n\n\n

Or, y(y \u2013 13) \u2013 8(y \u2013 13) = 0<\/p>\n\n\n\n

Or, (y \u2013 13)(y \u2013 8) = 0<\/p>\n\n\n\n

So, y = 13 or y = 8<\/p>\n\n\n\n

From III:<\/p>\n\n\n\n

z2<\/sup> = 4z + 32<\/p>\n\n\n\n

Or, z2<\/sup> \u2013 4z \u2013 32 = 0<\/p>\n\n\n\n

Or, z2 <\/sup>\u2013 8z + 4z \u2013 32 = 0<\/p>\n\n\n\n

Or, z(z \u2013 8) + 4(z \u2013 8) = 0<\/p>\n\n\n\n

Or, (z \u2013 8)(z + 4) = 0<\/p>\n\n\n\n

So, z = 8 or z = -4<\/p>\n\n\n\n

Therefore, correct relation is I – c, II – a, III \u2013 b.<\/p>\n\n\n\n

Hence, option d.<\/p>\n\n\n\n

Solution 9: C)<\/strong><\/p>\n\n\n\n

For series I:<\/p>\n\n\n\n

465 \u00d7 2 = 930<\/p>\n\n\n\n

930 \u00f7 3 = 310<\/p>\n\n\n\n

310 \u00d7 4 = 1240<\/p>\n\n\n\n

1240 \u00f7 5 = 248<\/strong><\/p>\n\n\n\n

248 \u00d7 6 = 1488<\/p>\n\n\n\n

Therefore, x = 248<\/p>\n\n\n\n

For series II:<\/p>\n\n\n\n

180 + (34 \u00d7 1) = 214<\/strong><\/p>\n\n\n\n

214 \u2013 (34 \u00d7 2) = 146<\/p>\n\n\n\n

146 + (34 \u00d7 3) = 248<\/p>\n\n\n\n

248 \u2013 (34 \u00d7 4) = 112<\/p>\n\n\n\n

112 + (34 \u00d7 5) = 282<\/p>\n\n\n\n

So, 214 is the missing number in series II.<\/p>\n\n\n\n

Hence, option c.<\/p>\n\n\n\n

Solution 10: B)<\/strong><\/p>\n\n\n\n

For series I:<\/p>\n\n\n\n

20 + 12 \u00d7 1 = 32<\/p>\n\n\n\n

32 + 12 \u00d7 2 = 56<\/strong><\/p>\n\n\n\n

56 + 12 \u00d7 3 = 92<\/p>\n\n\n\n

92 + 12 \u00d7 4 = 140<\/p>\n\n\n\n

140 + 12 \u00d7 5 = 200<\/p>\n\n\n\n

So, P = 62<\/p>\n\n\n\n

For series II:<\/p>\n\n\n\n

14 \u00d7 1 = 14<\/p>\n\n\n\n

14 \u00d7 1.5 = 21<\/p>\n\n\n\n

21 \u00d7 2 = 42<\/p>\n\n\n\n

42 \u00d7 2.5 = 105<\/strong><\/p>\n\n\n\n

105 \u00d7 3 = 315<\/p>\n\n\n\n

315 \u00d7 3.5 = 1102.5<\/p>\n\n\n\n

So, Q = 110<\/p>\n\n\n\n

For series III:<\/p>\n\n\n\n

124 \u2013 17 = 107<\/p>\n\n\n\n

107 \u2013 17 = 90<\/p>\n\n\n\n

90 \u2013 17 = 73<\/p>\n\n\n\n

73 \u2013 17 = 56<\/p>\n\n\n\n

56 \u2013 17 = 39<\/strong><\/p>\n\n\n\n

So, R = 42<\/p>\n\n\n\n

So, P < Q > R<\/p>\n\n\n\n

Hence, option b.<\/p>\n\n\n\n

Conclusion <\/h2>\n\n\n\n

Preparing for the Quantitative Aptitude section of the RBI Grade B 2024 exam requires a structured approach, conceptual clarity, regular practice, and time management skills. By understanding the exam pattern, focusing on core concepts, utilizing a variety of resources, and practicing with important questions, aspirants can enhance their preparation and boost their chances of success in the RBI Grade B exam.<\/p>\n\n\n\n

<\/p>\n\n\n\n

Disclaimer:<\/strong> The Quantitative Aptitude strategies, examples, and practice questions shared here are for guidance only. They are illustrative, not official RBI Grade B exam content. Actual exam questions may differ in wording, format, or difficulty. Candidates should always consult official RBI notices<\/a> for authentic and updated information.<\/p>\n\n\n\n

<\/p>\n","protected":false},"excerpt":{"rendered":"

Quantitative Aptitude Preparation Strategy 2024: Preparing for the Quantitative Aptitude section of the RBI Grade B 2024 exam requires a strategic approach to tackle the diverse range of mathematical concepts and problem-solving skills tested. 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I cleared many bank exams time by time but couldn't join because of my passion towards writing. I write blogs to help aspirants prepare for Banking and Insurance exams. These blogs turn out to be a one-stop destination for comprehensive information on some of the biggest competitive exams like SBI PO\/Clerk, IBPS PO\/Clerk, IBPS RRB PO\/Clerk and RBI. My ultimate goal is to provide accurate and easy-to-understand information, covering topics like exam patterns, syllabus, study techniques, and more. Join me on this journey of knowledge!","url":"https:\/\/www.practicemock.com\/blog\/author\/ss8860409gmail-com\/"}]}},"uagb_featured_image_src":{"full":["https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2024\/03\/Quantitative-Aptitude-Preparation-Strategy-Important-Question-for-RBI-Grade-B-2024.png",770,515,false],"thumbnail":["https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2024\/03\/Quantitative-Aptitude-Preparation-Strategy-Important-Question-for-RBI-Grade-B-2024.png",150,100,false],"medium":["https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2024\/03\/Quantitative-Aptitude-Preparation-Strategy-Important-Question-for-RBI-Grade-B-2024.png",300,201,false],"medium_large":["https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2024\/03\/Quantitative-Aptitude-Preparation-Strategy-Important-Question-for-RBI-Grade-B-2024.png",640,428,false],"large":["https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2024\/03\/Quantitative-Aptitude-Preparation-Strategy-Important-Question-for-RBI-Grade-B-2024.png",640,428,false],"1536x1536":["https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2024\/03\/Quantitative-Aptitude-Preparation-Strategy-Important-Question-for-RBI-Grade-B-2024.png",770,515,false],"2048x2048":["https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2024\/03\/Quantitative-Aptitude-Preparation-Strategy-Important-Question-for-RBI-Grade-B-2024.png",770,515,false],"web-stories-poster-portrait":["https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2024\/03\/Quantitative-Aptitude-Preparation-Strategy-Important-Question-for-RBI-Grade-B-2024.png",640,428,false],"web-stories-publisher-logo":["https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2024\/03\/Quantitative-Aptitude-Preparation-Strategy-Important-Question-for-RBI-Grade-B-2024.png",96,64,false],"web-stories-thumbnail":["https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2024\/03\/Quantitative-Aptitude-Preparation-Strategy-Important-Question-for-RBI-Grade-B-2024.png",150,100,false]},"uagb_author_info":{"display_name":"Sweta Singh","author_link":"https:\/\/www.practicemock.com\/blog\/author\/ss8860409gmail-com\/"},"uagb_comment_info":7,"uagb_excerpt":"Quantitative Aptitude Preparation Strategy 2024: Preparing for the Quantitative Aptitude section of the RBI Grade B 2024 exam requires a strategic approach to tackle the diverse range of mathematical concepts and problem-solving skills tested. This article aims to provide a comprehensive guide to crafting an effective preparation strategy, along with important questions tailored for the…","_links":{"self":[{"href":"https:\/\/www.practicemock.com\/blog\/wp-json\/wp\/v2\/posts\/80793","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.practicemock.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.practicemock.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.practicemock.com\/blog\/wp-json\/wp\/v2\/users\/13"}],"replies":[{"embeddable":true,"href":"https:\/\/www.practicemock.com\/blog\/wp-json\/wp\/v2\/comments?post=80793"}],"version-history":[{"count":0,"href":"https:\/\/www.practicemock.com\/blog\/wp-json\/wp\/v2\/posts\/80793\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.practicemock.com\/blog\/wp-json\/wp\/v2\/media\/80794"}],"wp:attachment":[{"href":"https:\/\/www.practicemock.com\/blog\/wp-json\/wp\/v2\/media?parent=80793"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.practicemock.com\/blog\/wp-json\/wp\/v2\/categories?post=80793"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.practicemock.com\/blog\/wp-json\/wp\/v2\/tags?post=80793"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}