{"id":71980,"date":"2023-12-14T14:41:01","date_gmt":"2023-12-14T09:11:01","guid":{"rendered":"https:\/\/www.practicemock.com\/blog\/?p=71980"},"modified":"2023-12-14T14:41:03","modified_gmt":"2023-12-14T09:11:03","slug":"new-type-of-equation-comparison-practice-questions-for-mains-exam","status":"publish","type":"post","link":"https:\/\/www.practicemock.com\/blog\/new-type-of-equation-comparison-practice-questions-for-mains-exam\/","title":{"rendered":"New Type of Equation Comparison Practice Questions for Mains Exam"},"content":{"rendered":"\n

RBI Assistant Mains is an upcoming important exam which is just around the corner. The exam is falling on 31st December thereby not leaving much time for practice. We are here trying to help the aspirants who are preparing for any mains examination especially RBI Assistant mains 2023. Here we are providing a few new type of Equation Comparison practice questions for mains exam which will be helpful for RBI Assistant mains<\/a>.\u00a0<\/p>\n\n\n\n

New Type of Equation Comparison Practice Questions for Mains Exam<\/h2>\n\n\n\n

Directions (1 \u2013 3):<\/strong> Answer the questions based on the information given below.<\/p>\n\n\n\n

I. 2x2<\/sup> + 7x + k = 0<\/p>\n\n\n\n

II. (ay + b)2<\/sup> = 0<\/p>\n\n\n\n

Smaller root of equation I is -2.<\/p>\n\n\n\n

Larger root of equation I is a root of equation II.<\/p>\n\n\n\n

Question 1:<\/strong> If p = -2 \u00d7 \u221a(k + 3), then find the value of \u2018p\u2019.<\/p>\n\n\n\n

A) 3<\/p>\n\n\n\n

B) 6<\/p>\n\n\n\n

C) -6<\/p>\n\n\n\n

D) 9<\/p>\n\n\n\n

E) None of these<\/p>\n\n\n\n

RBI Assistant Mains Free Mock Test<\/a><\/p>\n\n\n\n

Question 2:<\/strong> Find the value of \u2018b\u2019.<\/p>\n\n\n\n

A) 3<\/p>\n\n\n\n

B) -3<\/p>\n\n\n\n

C) 0<\/p>\n\n\n\n

D) -1<\/p>\n\n\n\n

E) Can\u2019t be determined<\/p>\n\n\n\n

Question 3:<\/strong> Find the other root of equation (I).<\/p>\n\n\n\n

A) 1.25<\/p>\n\n\n\n

B) -1.25<\/p>\n\n\n\n

C) 1.5<\/p>\n\n\n\n

D) -1.5<\/p>\n\n\n\n

E) 0.25<\/p>\n\n\n\n

Question 4:<\/strong> In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.<\/p>\n\n\n\n

I. x3<\/sup> \u2013 142<\/sup> + (322 <\/sup>\u2013 242<\/sup>) = 154 + 212<\/sup><\/p>\n\n\n\n

II. y2<\/sup>\u2013 12y + 35 = 0<\/p>\n\n\n\n

A) x > y<\/p>\n\n\n\n

B) x < y<\/p>\n\n\n\n

C) x = y or the relationship cannot be established<\/p>\n\n\n\n

D) x \u2265 y<\/p>\n\n\n\n

E) x \u2264 y<\/p>\n\n\n\n

Question 5:<\/strong> In the questions, three equations I, II and III are given. You have to solve the equations to establish the correct relation. Which of the following pair of symbols will define the relation between x and y and between y and z?<\/p>\n\n\n\n

I. 3x + 2y + 4z = 61<\/p>\n\n\n\n

II. x + 5y + z = 53<\/p>\n\n\n\n

III. 5x + y + z = 49<\/p>\n\n\n\n

A. =<\/p>\n\n\n\n

B. ><\/p>\n\n\n\n

C. <<\/p>\n\n\n\n

D. >=<\/p>\n\n\n\n

E. <=<\/p>\n\n\n\n

F. # (relation cannot be established)<\/p>\n\n\n\n

A) B, C<\/p>\n\n\n\n

B) D, C<\/p>\n\n\n\n

C) F, D<\/p>\n\n\n\n

D) C, B<\/p>\n\n\n\n

E) F, C<\/p>\n\n\n\n

RBI Assistant Mains Free Mock Test<\/a><\/p>\n\n\n\n

Question 6:<\/strong> In the given table there are two columns I and II. Column I contains three equations and column II contains the roots of the equations given in column I, not necessarily in the same order. Study the given table carefully and answer the questions accordingly.<\/p>\n\n\n\n

Column I<\/td>Column II<\/td><\/tr>
I. x2<\/sup> \u2013 3x = 28<\/td>a.) (8,13)<\/td><\/tr>
II. y2 <\/sup>+ 104 = 21y<\/td>b.) (-4, 8)<\/td><\/tr>
III. z2 <\/sup>= 4z + 32<\/td>c.) (7, -4)<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

Which of the following relation is correct?<\/p>\n\n\n\n

A) I – a, II – b, III – c<\/p>\n\n\n\n

B) I – a, II – c, III – b<\/p>\n\n\n\n

C) I – c, II – b, III – a<\/p>\n\n\n\n

D) I – c, II – a, III – b<\/p>\n\n\n\n

E) I – b, II – a, III – c<\/p>\n\n\n\n

Question 7:<\/strong> Which of the following pair of symbols will define the relation between x and y and between y and z respectively?<\/p>\n\n\n\n

A. =<\/p>\n\n\n\n

B. ><\/p>\n\n\n\n

C. <<\/p>\n\n\n\n

D. \u2265<\/p>\n\n\n\n

E. \u2264<\/p>\n\n\n\n

F. # (relation cannot be established)<\/p>\n\n\n\n

I. 4x2<\/sup> \u2013 20x + 21 = 0<\/p>\n\n\n\n

II. 2y2<\/sup> = y + 3<\/p>\n\n\n\n

III. 5z2<\/sup> \u2013 24z + 28 = 0<\/p>\n\n\n\n

A) C, D<\/p>\n\n\n\n

B) F, C<\/p>\n\n\n\n

C) C, B<\/p>\n\n\n\n

D) D, C<\/p>\n\n\n\n

E) F, B<\/p>\n\n\n\n

Question 8:<\/strong> Which of the following pair of symbols will define the relation between x and y and between y and z respectively?<\/p>\n\n\n\n

A. =<\/p>\n\n\n\n

B. ><\/p>\n\n\n\n

C. <<\/p>\n\n\n\n

D. \u2265<\/p>\n\n\n\n

E. \u2264<\/p>\n\n\n\n

F. # (relation cannot be established)<\/p>\n\n\n\n

I. x + 7y \u2013 2z = 28<\/p>\n\n\n\n

II. 9x \u2013 4y + 5z = 76<\/p>\n\n\n\n

III. 5x \u2013 6y + 4z = 32<\/p>\n\n\n\n

A) B, C<\/p>\n\n\n\n

B) A, C<\/p>\n\n\n\n

C) B, A<\/p>\n\n\n\n

D) C, B<\/p>\n\n\n\n

E) C, A<\/p>\n\n\n\n

RBI Assistant Mains Free Mock Test<\/a><\/p>\n\n\n\n

Question 9:<\/strong> In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.<\/p>\n\n\n\n

I. x2<\/sup> + (7 + 6\u221a2)x + 42\u221a2 = 0<\/p>\n\n\n\n

II. y2<\/sup> + 13\u221a2y + 84 = 0<\/p>\n\n\n\n

A) x > y<\/p>\n\n\n\n

B) x < y<\/p>\n\n\n\n

C) x = y or the relationship cannot be established<\/p>\n\n\n\n

D) x \u2265 y<\/p>\n\n\n\n

E) x \u2264 y<\/p>\n\n\n\n

\u0928\u093f\u0930\u094d\u0926\u0947\u0936 (1 \u2013 3):<\/strong> \u0928\u0940\u091a\u0947 \u0926\u0940 \u0917\u0908 \u091c\u093e\u0928\u0915\u093e\u0930\u0940 \u0915\u0947 \u0906\u0927\u093e\u0930 \u092a\u0930 \u092a\u094d\u0930\u0936\u094d\u0928\u094b\u0902 \u0915\u0947 \u0909\u0924\u094d\u0924\u0930 \u0926\u0947\u0902\u0964<\/p>\n\n\n\n

I. 2x2<\/sup> + 7x + k = 0<\/p>\n\n\n\n

II. (ay + b)2<\/sup> = 0<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 I \u0915\u093e \u091b\u094b\u091f\u093e \u0938\u0942\u0924\u094d\u0930 -2 \u0939\u0948\u0964<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 I \u0915\u093e \u092c\u0921\u093c\u093e \u0938\u0942\u0924\u094d\u0930 \u0938\u092e\u0940\u0915\u0930\u0923 II \u0915\u093e \u0938\u0942\u0924\u094d\u0930 \u0939\u0948\u0964<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 1:<\/strong> \u092f\u0926\u093f p = -2 \u00d7 \u221a(k + 3) \u0939\u0948, \u0924\u094b \u2018p\u2019 \u0915\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947\u0902\u0964<\/p>\n\n\n\n

A) 3<\/p>\n\n\n\n

B) 6<\/p>\n\n\n\n

C) -6<\/p>\n\n\n\n

D) 9<\/p>\n\n\n\n

E) \u0907\u0928\u092e\u0947\u0902 \u0938\u0947 \u0915\u094b\u0908 \u0928\u0939\u0940\u0902<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 2:<\/strong> \u2018b\u2019 \u0915\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947\u0902\u0964<\/p>\n\n\n\n

A) 3<\/p>\n\n\n\n

B) -3<\/p>\n\n\n\n

C) 0<\/p>\n\n\n\n

D) -1<\/p>\n\n\n\n

E) \u0928\u093f\u0930\u094d\u0927\u093e\u0930\u093f\u0924 \u0928\u0939\u0940\u0902 \u0915\u093f\u092f\u093e \u091c\u093e \u0938\u0915\u0924\u093e \u0939\u0948<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 3:<\/strong> \u0938\u092e\u0940\u0915\u0930\u0923 (I) \u0915\u0940 \u0926\u0942\u0938\u0930\u093e \u0938\u0942\u0924\u094d\u0930 \u0916\u094b\u091c\u0947\u0902\u0964<\/p>\n\n\n\n

A) 1.25<\/p>\n\n\n\n

B) -1.25<\/p>\n\n\n\n

C) 1.5<\/p>\n\n\n\n

D) -1.5<\/p>\n\n\n\n

E) 0.25<\/p>\n\n\n\n

RBI Assistant Mains Free Mock Test<\/a><\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 4:<\/strong> \u092a\u094d\u0930\u0936\u094d\u0928 \u092e\u0947\u0902, \u0926\u094b \u0938\u092e\u0940\u0915\u0930\u0923 I \u0914\u0930 II \u0926\u093f\u090f \u0917\u090f \u0939\u0948\u0902\u0964 \u0906\u092a\u0915\u094b x \u0914\u0930 y \u0915\u0947 \u092c\u0940\u091a \u0938\u0939\u0940 \u0938\u0902\u092c\u0902\u0927 \u0938\u094d\u0925\u093e\u092a\u093f\u0924 \u0915\u0930\u0928\u0947 \u0914\u0930 \u0938\u0939\u0940 \u0935\u093f\u0915\u0932\u094d\u092a \u091a\u0941\u0928\u0928\u0947 \u0915\u0947 \u0932\u093f\u090f \u0926\u094b\u0928\u094b\u0902 \u0938\u092e\u0940\u0915\u0930\u0923\u094b\u0902 \u0915\u094b \u0939\u0932 \u0915\u0930\u0928\u093e \u0939\u094b\u0917\u093e\u0964<\/p>\n\n\n\n

I.x3<\/sup> \u2013 142<\/sup> + (322 <\/sup>\u2013 242<\/sup>) = 154 + 212<\/sup><\/p>\n\n\n\n

II. y2<\/sup>\u2013 12y + 35 = 0<\/p>\n\n\n\n

A) x > y<\/p>\n\n\n\n

B) x < y<\/p>\n\n\n\n

C) x = y \u092f\u093e \u0938\u0902\u092c\u0902\u0927 \u0938\u094d\u0925\u093e\u092a\u093f\u0924 \u0928\u0939\u0940\u0902 \u0915\u093f\u092f\u093e \u091c\u093e \u0938\u0915\u0924\u093e \u0939\u0948 <\/p>\n\n\n\n

D) x \u2265 y<\/p>\n\n\n\n

E) x \u2264 y<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 5:<\/strong> \u092a\u094d\u0930\u0936\u094d\u0928\u094b\u0902 \u092e\u0947\u0902, \u0924\u0940\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 I, II \u0914\u0930 III \u0926\u093f\u090f \u0917\u090f \u0939\u0948\u0902\u0964 \u0906\u092a\u0915\u094b \u0938\u0939\u0940 \u0938\u0902\u092c\u0902\u0927 \u0938\u094d\u0925\u093e\u092a\u093f\u0924 \u0915\u0930\u0928\u0947 \u0915\u0947 \u0932\u093f\u090f \u0938\u092e\u0940\u0915\u0930\u0923\u094b\u0902 \u0915\u094b \u0939\u0932 \u0915\u0930\u0928\u093e \u0939\u094b\u0917\u093e\u0964 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0938\u0947 \u0915\u094c\u0928 \u0938\u093e \u092a\u094d\u0930\u0924\u0940\u0915 x \u0914\u0930 y \u0914\u0930 y \u0914\u0930 z \u0915\u0947 \u092c\u0940\u091a \u0915\u0947 \u0938\u0902\u092c\u0902\u0927 \u0915\u094b \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0915\u0930\u0947\u0917\u093e?<\/p>\n\n\n\n

I. 3x + 2y + 4z = 61<\/p>\n\n\n\n

II. x + 5y + z = 53<\/p>\n\n\n\n

III. 5x + y + z = 49<\/p>\n\n\n\n

A. =<\/p>\n\n\n\n

B. ><\/p>\n\n\n\n

C. <<\/p>\n\n\n\n

D. >=<\/p>\n\n\n\n

E. <=<\/p>\n\n\n\n

F. # (\u0938\u0902\u092c\u0902\u0927 \u0938\u094d\u0925\u093e\u092a\u093f\u0924 \u0928\u0939\u0940\u0902 \u0915\u093f\u092f\u093e \u091c\u093e \u0938\u0915\u0924\u093e)<\/p>\n\n\n\n

A) B, C<\/p>\n\n\n\n

B) D, C<\/p>\n\n\n\n

C) F, D<\/p>\n\n\n\n

D) C, B<\/p>\n\n\n\n

E) F, C<\/p>\n\n\n\n

RBI Assistant Mains Free Mock Test<\/a><\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 6:<\/strong> \u0926\u0940 \u0917\u0908 \u0924\u093e\u0932\u093f\u0915\u093e \u092e\u0947\u0902 \u0926\u094b \u0915\u0949\u0932\u092e I \u0914\u0930 II \u0939\u0948\u0902\u0964 \u0915\u0949\u0932\u092e I \u092e\u0947\u0902 \u0924\u0940\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948\u0902 \u0914\u0930 \u0915\u0949\u0932\u092e II \u092e\u0947\u0902 \u0915\u0949\u0932\u092e I \u092e\u0947\u0902 \u0926\u093f\u090f \u0917\u090f \u0938\u092e\u0940\u0915\u0930\u0923\u094b\u0902 \u0915\u0947 \u0938\u0942\u0924\u094d\u0930 \u0939\u0948\u0902, \u091c\u093c\u0930\u0942\u0930\u0940 \u0928\u0939\u0940\u0902 \u0915\u093f \u0907\u0938\u0940 \u0915\u094d\u0930\u092e \u092e\u0947\u0902 \u0939\u094b\u0902\u0964 \u0926\u0940 \u0917\u0908 \u0924\u093e\u0932\u093f\u0915\u093e \u0915\u093e \u0927\u094d\u092f\u093e\u0928\u092a\u0942\u0930\u094d\u0935\u0915 \u0905\u0927\u094d\u092f\u092f\u0928 \u0915\u0930\u0947\u0902 \u0914\u0930 \u0909\u0938\u0915\u0947 \u0905\u0928\u0941\u0938\u093e\u0930 \u092a\u094d\u0930\u0936\u094d\u0928\u094b\u0902 \u0915\u0947 \u0909\u0924\u094d\u0924\u0930 \u0926\u0947\u0902\u0964<\/p>\n\n\n\n

Column I<\/td>Column II<\/td><\/tr>
I. x2<\/sup> \u2013 3x = 28<\/td>a.) (8,13)<\/td><\/tr>
II. y2 <\/sup>+ 104 = 21y<\/td>b.) (-4, 8)<\/td><\/tr>
III. z2 <\/sup>= 4z + 32<\/td>c.) (7, -4)<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0938\u0947 \u0915\u094c\u0928 \u0938\u093e \u0938\u0902\u092c\u0902\u0927 \u0938\u0939\u0940 \u0939\u0948?<\/p>\n\n\n\n

A) I – a, II – b, III – c<\/p>\n\n\n\n

B) I – a, II – c, III – b<\/p>\n\n\n\n

C) I – c, II – b, III – a<\/p>\n\n\n\n

D) I – c, II – a, III – b<\/p>\n\n\n\n

E) I – b, II – a, III – c<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 7:<\/strong> \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0938\u0947 \u0915\u094c\u0928 \u0938\u093e \u092a\u094d\u0930\u0924\u0940\u0915 \u0915\u094d\u0930\u092e\u0936\u0903 x \u0914\u0930 y \u0914\u0930 y \u0914\u0930 z \u0915\u0947 \u092c\u0940\u091a \u0915\u0947 \u0938\u0902\u092c\u0902\u0927 \u0915\u094b \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0915\u0930\u0947\u0917\u093e?<\/p>\n\n\n\n

A. =<\/p>\n\n\n\n

B. ><\/p>\n\n\n\n

C. <<\/p>\n\n\n\n

D. \u2265<\/p>\n\n\n\n

E. \u2264<\/p>\n\n\n\n

F. # (\u0938\u0902\u092c\u0902\u0927 \u0938\u094d\u0925\u093e\u092a\u093f\u0924 \u0928\u0939\u0940\u0902 \u0915\u093f\u092f\u093e \u091c\u093e \u0938\u0915\u0924\u093e)<\/p>\n\n\n\n

I. 4x2<\/sup> \u2013 20x + 21 = 0<\/p>\n\n\n\n

II. 2y2<\/sup> = y + 3<\/p>\n\n\n\n

III. 5z2<\/sup> \u2013 24z + 28 = 0<\/p>\n\n\n\n

A) C, D<\/p>\n\n\n\n

B) F, C<\/p>\n\n\n\n

C) C, B<\/p>\n\n\n\n

D) D, C<\/p>\n\n\n\n

E) F, B<\/p>\n\n\n\n

RBI Assistant Mains Free Mock Test<\/a><\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 8:<\/strong> \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0938\u0947 \u0915\u094c\u0928 \u0938\u093e \u092a\u094d\u0930\u0924\u0940\u0915 \u0915\u094d\u0930\u092e\u0936 : x \u0914\u0930 y \u0914\u0930 y \u0914\u0930 z \u0915\u0947 \u092c\u0940\u091a \u0915\u0947 \u0938\u0902\u092c\u0902\u0927 \u0915\u094b \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0915\u0930\u0947\u0917\u093e?<\/p>\n\n\n\n

A. =<\/p>\n\n\n\n

B. ><\/p>\n\n\n\n

C. <<\/p>\n\n\n\n

D. \u2265<\/p>\n\n\n\n

E. \u2264<\/p>\n\n\n\n

F. # (\u0938\u0902\u092c\u0902\u0927 \u0938\u094d\u0925\u093e\u092a\u093f\u0924 \u0928\u0939\u0940\u0902 \u0915\u093f\u092f\u093e \u091c\u093e \u0938\u0915\u0924\u093e)<\/p>\n\n\n\n

I. x + 7y \u2013 2z = 28<\/p>\n\n\n\n

II. 9x \u2013 4y + 5z = 76<\/p>\n\n\n\n

III. 5x \u2013 6y + 4z = 32<\/p>\n\n\n\n

A) B, C<\/p>\n\n\n\n

B) A, C<\/p>\n\n\n\n

C) B, A<\/p>\n\n\n\n

D) C, B<\/p>\n\n\n\n

E) C, A<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 9:<\/strong> \u092a\u094d\u0930\u0936\u094d\u0928 \u092e\u0947\u0902, \u0926\u094b \u0938\u092e\u0940\u0915\u0930\u0923 I \u0914\u0930 II \u0926\u093f\u090f \u0917\u090f \u0939\u0948\u0902\u0964 \u0906\u092a\u0915\u094b x \u0914\u0930 y \u0915\u0947 \u092c\u0940\u091a \u0938\u0939\u0940 \u0938\u0902\u092c\u0902\u0927 \u0938\u094d\u0925\u093e\u092a\u093f\u0924 \u0915\u0930\u0928\u0947 \u0914\u0930 \u0938\u0939\u0940 \u0935\u093f\u0915\u0932\u094d\u092a \u091a\u0941\u0928\u0928\u0947 \u0915\u0947 \u0932\u093f\u090f \u0926\u094b\u0928\u094b\u0902 \u0938\u092e\u0940\u0915\u0930\u0923\u094b\u0902 \u0915\u094b \u0939\u0932 \u0915\u0930\u0928\u093e \u0939\u094b\u0917\u093e\u0964<\/p>\n\n\n\n

I. x2<\/sup> + (7 + 6\u221a2)x + 42\u221a2 = 0<\/p>\n\n\n\n

II. y2<\/sup> + 13\u221a2y + 84 = 0<\/p>\n\n\n\n

A) x > y<\/p>\n\n\n\n

B) x < y<\/p>\n\n\n\n

C) x = y \u092f\u093e \u0938\u0902\u092c\u0902\u0927 \u0938\u094d\u0925\u093e\u092a\u093f\u0924 \u0928\u0939\u0940\u0902 \u0915\u093f\u092f\u093e \u091c\u093e \u0938\u0915\u0924\u093e \u0939\u0948<\/p>\n\n\n\n

D) x \u2265 y<\/p>\n\n\n\n

E) x \u2264 y<\/p>\n\n\n\n

RBI Assistant Mains Free Mock Test<\/a><\/p>\n\n\n\n

ANSWER KEYS and SOLUTIONS:<\/strong><\/h4>\n\n\n\n
1) – C)<\/td>2) – E)<\/td>3) – D)<\/td>4) – D)<\/td>5) – D)<\/td>6) – D)<\/td><\/tr>
7) – D)<\/td>8) – C)<\/td>9) – D)<\/td> <\/td> <\/td> <\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

Solution 1: C)<\/strong><\/p>\n\n\n\n

Since, (-2) is a root of equation I,<\/p>\n\n\n\n

2 \u00d7 (-2)2<\/sup> 7 \u00d7 (-2) k = 0<\/p>\n\n\n\n

Or, 2 \u00d7 4 (-14) k = 0<\/p>\n\n\n\n

Or, 8 \u2013 14 k = 0<\/p>\n\n\n\n

Or, k = 6<\/p>\n\n\n\n

So, 2x2<\/sup> 7x 6 = 0<\/p>\n\n\n\n

Or, 2x2<\/sup> 4x \u2013 3x 6 = 0<\/p>\n\n\n\n

Or, 2x(x 2) 3(x 2) = 0<\/p>\n\n\n\n

Or, (x 2) (2x 3) = 0<\/p>\n\n\n\n

So, x = -2 or x = -(3\/2)<\/p>\n\n\n\n

Since, k = 6, required value = -2 \u00d7 \u221a(6 + 3) = -2 \u00d7 3 = -6<\/p>\n\n\n\n

Hence, option c.<\/p>\n\n\n\n

Solution 2: E)<\/strong><\/p>\n\n\n\n

Given = (ay + b)2<\/sup> = 0<\/p>\n\n\n\n

Or, ay + b = 0<\/p>\n\n\n\n

So, y = -(b\/a)<\/p>\n\n\n\n

Or, -(b\/a) = -(3\/2)<\/p>\n\n\n\n

Or, (b\/a) = (3\/2)<\/p>\n\n\n\n

Therefore, actual value of \u2018b\u2019 cannot be determined.<\/p>\n\n\n\n

Hence, option e.<\/p>\n\n\n\n

Solution 3: D)<\/strong><\/p>\n\n\n\n

So the other root of equation (I) is -3\/2 = -1.5.<\/p>\n\n\n\n

Hence, option d.<\/p>\n\n\n\n

RBI Assistant Mains Free Mock Test<\/a><\/p>\n\n\n\n

Solution 4: D)<\/strong><\/p>\n\n\n\n

From I:<\/p>\n\n\n\n

x3<\/sup> \u2013 142<\/sup> + (322 <\/sup>\u2013 242<\/sup>) = 154 + 212<\/sup><\/p>\n\n\n\n

x3<\/sup> \u2013 196 + (32 + 24)(32 \u2013 24) = 154 + 441<\/p>\n\n\n\n

x3<\/sup> \u2013 196 + 448 = 595<\/p>\n\n\n\n

x3<\/sup> = 343<\/p>\n\n\n\n

x = 7<\/p>\n\n\n\n

From II:<\/p>\n\n\n\n

y2<\/sup> \u2013 12y + 35 = 0<\/p>\n\n\n\n

y2<\/sup> \u2013 7y \u2013 5y +35 = 0<\/p>\n\n\n\n

y(y \u2013 7) \u2013 5(y \u2013 7) = 0<\/p>\n\n\n\n

(y \u2013 7)(y \u2013 5) = 0<\/p>\n\n\n\n

y = 7, 5<\/p>\n\n\n\n

So, x \u2265 y.<\/p>\n\n\n\n

Hence, option d.<\/p>\n\n\n\n

Solution 5: D)<\/strong><\/p>\n\n\n\n

From I and II,<\/p>\n\n\n\n

3x + 2y + 4z = 61<\/p>\n\n\n\n

z = (61 \u2013 3x \u2013 2y)\/4 ———-(a)<\/p>\n\n\n\n

And, x + 5y + z = 53<\/p>\n\n\n\n

z = 53 \u2013 x \u2013 5y ———(b)<\/p>\n\n\n\n

Solving (a) and (b), we get<\/p>\n\n\n\n

(61 \u2013 3x \u2013 2y)\/4 = 53 \u2013 x \u2013 5y<\/p>\n\n\n\n

x + 18y = 151 ——-(i)<\/p>\n\n\n\n

From II and III,<\/p>\n\n\n\n

x + 5y + z = 53<\/p>\n\n\n\n

z = 53 \u2013 x \u2013 5y ——-(c)<\/p>\n\n\n\n

And, 5x + y + z = 49<\/p>\n\n\n\n

z = 49 \u2013 5x \u2013 y ———(d)<\/p>\n\n\n\n

Solving (c) and (d), we get<\/p>\n\n\n\n

53 \u2013 x \u2013 5y = 49 \u2013 5x \u2013 y<\/p>\n\n\n\n

y \u2013 x = 1 ———(ii)<\/p>\n\n\n\n

Solving (i) and (ii), we get<\/p>\n\n\n\n

y = 8 and x = 7,<\/p>\n\n\n\n

So, z = 6<\/p>\n\n\n\n

Hence, option d.<\/p>\n\n\n\n

Solution 6: D)<\/strong><\/p>\n\n\n\n

From I:<\/p>\n\n\n\n

x2<\/sup> \u2013 3x = 28<\/p>\n\n\n\n

Or, x2<\/sup> \u2013 3x \u2013 28 = 0<\/p>\n\n\n\n

Or, x2<\/sup> \u2013 7x + 4x \u2013 28 = 0<\/p>\n\n\n\n

Or, x(x \u2013 7) + 4(x \u2013 7) = 0<\/p>\n\n\n\n

Or, (x \u2013 7)(x + 4) = 0<\/p>\n\n\n\n

So, x = 7 or x = -4<\/p>\n\n\n\n

From II:<\/p>\n\n\n\n

y2 <\/sup>+ 104 = 21y<\/p>\n\n\n\n

Or, y2<\/sup> \u2013 21y + 104 = 0<\/p>\n\n\n\n

Or, y2<\/sup> \u2013 13y \u2013 8y + 104 = 0<\/p>\n\n\n\n

Or, y(y \u2013 13) \u2013 8(y \u2013 13) = 0<\/p>\n\n\n\n

Or, (y \u2013 13)(y \u2013 8) = 0<\/p>\n\n\n\n

So, y = 13 or y = 8<\/p>\n\n\n\n

From III:<\/p>\n\n\n\n

z2<\/sup> = 4z + 32<\/p>\n\n\n\n

Or, z2<\/sup> \u2013 4z \u2013 32 = 0<\/p>\n\n\n\n

Or, z2 <\/sup>\u2013 8z + 4z \u2013 32 = 0<\/p>\n\n\n\n

Or, z(z \u2013 8) + 4(z \u2013 8) = 0<\/p>\n\n\n\n

Or, (z \u2013 8)(z + 4) = 0<\/p>\n\n\n\n

So, z = 8 or z = -4<\/p>\n\n\n\n

Therefore, correct relation is I – c, II – a, III \u2013 b.<\/p>\n\n\n\n

Hence, option d.<\/p>\n\n\n\n

RBI Assistant Mains Free Mock Test<\/a><\/p>\n\n\n\n

Solution 7: D)<\/strong><\/p>\n\n\n\n

From I:<\/p>\n\n\n\n

4x2<\/sup> \u2013 20x + 21 = 0<\/p>\n\n\n\n

4x2<\/sup> \u2013 14x \u2013 6x + 21 = 0<\/p>\n\n\n\n

2x(2x \u2013 7) \u2013 3(2x \u2013 7) = 0<\/p>\n\n\n\n

(2x \u2013 7)(2x \u2013 3) = 0<\/p>\n\n\n\n

x = 7\/2, 3\/2<\/p>\n\n\n\n

From II:<\/p>\n\n\n\n

2y2<\/sup> = y + 3<\/p>\n\n\n\n

2y2<\/sup> \u2013 y \u2013 3 = 0<\/p>\n\n\n\n

2y2<\/sup>\u2013 3y + 2y \u2013 3 = 0<\/p>\n\n\n\n

y(2y \u2013 3) + 1(2y \u2013 3) = 0<\/p>\n\n\n\n

(y + 1)(2y \u2013 3) = 0<\/p>\n\n\n\n

y = -1, 3\/2<\/p>\n\n\n\n

From III:<\/p>\n\n\n\n

5z2<\/sup> \u2013 24z + 28 = 0<\/p>\n\n\n\n

5z2<\/sup> \u2013 14z \u2013 10z + 28 = 0<\/p>\n\n\n\n

z(5z \u2013 14) \u2013 2(5z \u2013 14) = 0<\/p>\n\n\n\n

(5z \u2013 14)(z \u2013 2) = 0<\/p>\n\n\n\n

z = 2, 14\/5<\/p>\n\n\n\n

So, x \u2265 y and y < z.<\/p>\n\n\n\n

Hence, option d.<\/p>\n\n\n\n

Solution 8: C)<\/strong><\/p>\n\n\n\n

Using equations (I) and (II):<\/p>\n\n\n\n

9 \u00d7 (28 \u2013 7y + 2z) \u2013 4y + 5z = 76<\/p>\n\n\n\n

252 \u2013 63y + 18z \u2013 4y + 5z = 76<\/p>\n\n\n\n

67y \u2013 23z = 176<\/p>\n\n\n\n

y = (176 + 23z)\/67 ———-(i)<\/p>\n\n\n\n

Using equations (I) and (III):<\/p>\n\n\n\n

5 \u00d7 (28 \u2013 7y + 2z) \u2013 6y + 4z = 32<\/p>\n\n\n\n

140 \u2013 35y + 10z \u2013 6y + 4z = 32<\/p>\n\n\n\n

41y \u2013 14z = 108<\/p>\n\n\n\n

Using (I), 41 \u00d7 (176 + 23z)\/67 \u2013 14z = 108<\/p>\n\n\n\n

7216 + 943z \u2013 938z = 7236<\/p>\n\n\n\n

5z = 20<\/p>\n\n\n\n

z = 4<\/p>\n\n\n\n

y = (176 + 23 \u00d7 4)\/67 = 268\/67 = 4<\/p>\n\n\n\n

x = 28 \u2013 7 \u00d7 4 + 2 \u00d7 4 = 28 \u2013 28 + 8 = 8<\/p>\n\n\n\n

So, x = 8, y = 4 and z = 4<\/p>\n\n\n\n

So, x >y and y = z.<\/p>\n\n\n\n

Hence, option c.<\/p>\n\n\n\n

Solution 9: D)<\/strong><\/p>\n\n\n\n

From I:<\/p>\n\n\n\n

x2<\/sup> + (7 + 6\u221a2)x + 42\u221a2 = 0<\/p>\n\n\n\n

x2<\/sup> + 7x + 6\u221a2x + 42\u221a2 = 0<\/p>\n\n\n\n

x(x + 7) + 6\u221a2(x + 7) = 0<\/p>\n\n\n\n

(x + 7)(x + 6\u221a2) = 0<\/p>\n\n\n\n

x = -7,-6\u221a2<\/p>\n\n\n\n

From II:<\/p>\n\n\n\n

y2<\/sup> + 13\u221a2y + 84 = 0<\/p>\n\n\n\n

y2<\/sup> + 7\u221a2y + 6\u221a2y + 84 = 0<\/p>\n\n\n\n

y(y + 7\u221a2) + 6\u221a2(y + 7\u221a2) = 0<\/p>\n\n\n\n

(y + 7\u221a2)(y + 6\u221a2) = 0<\/p>\n\n\n\n

y = -7\u221a2, -6\u221a2<\/p>\n\n\n\n

So, x \u2265 y.<\/p>\n\n\n\n

Hence, option d.<\/p>\n\n\n\n

RBI Assistant Mains Free Mock Test<\/a><\/p>\n\n\n\n

This is what the blog is all about. Make sure that you practice these new types of questions and know how many of these you could easily answer. <\/p>\n","protected":false},"excerpt":{"rendered":"

Practice these New Type of Equation Comparison Practice Questions for Mains Exam. Take Free Mock Test of RBI Assistant Mains exam<\/p>\n","protected":false},"author":2,"featured_media":71981,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_uag_custom_page_level_css":"","_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_uf_show_specific_survey":0,"_uf_disable_surveys":false,"footnotes":""},"categories":[2],"tags":[],"class_list":["post-71980","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-rbi-assistant"],"yoast_head":"\nNew Type of Equation Comparison Practice Questions for Mains Exam - Practicemock<\/title>\n<meta name=\"description\" content=\"Practice these New Type of Equation Comparison Practice Questions for Mains Exam. 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