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The SEBI Grade A 2025 Exam is one of the most prestigious banking and finance recruitment exams in India. The Quantitative Aptitude section plays a major role in both Phase 1 and Paper 1 exams. Among all the important topics, the Quadratic Equation is one of the most scoring and time-efficient chapters, provided you understand the concept well. In this article, we\u2019ll cover the key concepts, formulas, question patterns, and preparation strategy to help you master Quadratic Equations for SEBI Grade A 2025.<\/p>\n\n\n\n
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What is a Quadratic Equation?<\/h2>\n\n\n\n
A Quadratic Equation is a polynomial equation of degree 2, generally represented as:<\/p>\n\n\n
![\"\"](\"https:\/\/www.practicemock.com\/blog\/wp-content\/uploads\/2025\/10\/Screenshot-2025-10-31-151606.png\")
<\/figure><\/div>\n\n\nwhere,<\/p>\n\n\n\n
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- ( a, b, c ) are constants, and<\/li>\n\n\n\n
- ( a \u2260 0 ).<\/li>\n<\/ul>\n\n\n\n
The variable ( x ) is the unknown, and the goal is to find its roots or solutions.<\/p>\n\n\n\n
Standard Form & Components<\/h3>\n\n\n\n
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- Standard form<\/strong> \u2192 ( ax^2 + bx + c = 0 )<\/li>\n\n\n\n
- Coefficient of ( x^2 )<\/strong> \u2192 ( a )<\/li>\n\n\n\n
- Coefficient of ( x )<\/strong> \u2192 ( b )<\/li>\n\n\n\n
- Constant term<\/strong> \u2192 ( c )<\/li>\n<\/ul>\n\n\n\n
The solutions of this equation are called roots of the quadratic equation<\/strong>.<\/p>\n\n\n\n
Quadratic Equation Questions PDF Link with Detailed Solution<\/h2>\n\n\n\n
Download the Quadratic Equation Questions PDF with detailed solutions to practice important questions easily.
This PDF helps you understand each step clearly, learn quick tricks, and improve your speed and accuracy for the exam.<\/p>\n\n\n\nQuadratic Equation Questions PDF Link with Detailed Solution<\/a><\/h3>\n\n\n\n
Types of Questions Asked in SEBI Grade A Exam<\/h2>\n\n\n\n
In the SEBI Grade A Quant Section, questions on Quadratic Equations usually appear in the comparison-based format, where you have to compare the values of two variables ( x ) and ( y ).<\/p>\n\n\n\n
Example Type 1:<\/h3>\n\n\n\n
Solve the following and find the relation between ( x ) and ( y ).<\/p>\n\n\n\n
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- ( x^2 + 5x + 6 = 0 )
<\/li>\n\n\n\n - ( y^2 + 7y + 10 = 0 )<\/li>\n<\/ol>\n\n\n\n
Step 1:<\/strong> Solve for ( x ):
( x^2 + 5x + 6 = 0 ) \u2192 ( (x + 2)(x + 3) = 0 )
\u27f9 ( x = -2, -3 )<\/p>\n\n\n\nStep 2:<\/strong> Solve for ( y ):
( y^2 + 7y + 10 = 0 ) \u2192 ( (y + 2)(y + 5) = 0 )
\u27f9 ( y = -2, -5 )<\/p>\n\n\n\nStep 3:<\/strong> Compare:
For both roots, ( x \u2265 y )
Answer: x \u2265 y<\/strong><\/p>\n\n\n\nExample Type 2:<\/h3>\n\n\n\n
Find the nature of the roots of ( 2x^2 + 4x + 2 = 0 ).<\/p>\n\n\n\n
Here, ( a = 2, b = 4, c = 2 )
( D = b^2 – 4ac = 16 – 16 = 0 )<\/p>\n\n\n\nRoots are real and equal<\/strong>.<\/p>\n\n\n\n
Common Tricks for Fast Solving<\/h2>\n\n\n\n
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- Factorisation Method:<\/strong>
<\/strong> Split the middle term for faster root calculation (ideal for simple numbers).
<\/li>\n\n\n\n- Sign Pattern Recognition:<\/strong>
<\/strong> If both signs before ( x ) and the constant term are positive<\/strong>, both roots are negative<\/strong>, and vice versa.
<\/li>\n\n\n\n- Use Substitution Technique:<\/strong>
<\/strong> When coefficients are not simple, divide the equation by ( a ) to simplify.
<\/li>\n\n\n\n- Eliminate Options Smartly:<\/strong>
<\/strong> In comparison-based questions, find approximate roots using basic estimation to save time.
<\/li>\n\n\n\n- Avoid Square Root Errors:<\/strong>
<\/strong> Always check the discriminant ( D ) carefully to prevent calculation mistakes.<\/li>\n<\/ol>\n\n\n\nStrategy to Solve Quadratic Equation Questions Fast<\/h2>\n\n\n\n
When it comes to Quadratic Equation questions in the SEBI Grade A exam, my main focus is on speed and accuracy. Here\u2019s exactly how I solve them step by step<\/p>\n\n\n\n
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- First, I quickly identify the coefficients (a, b, c)<\/strong> from both equations.
Example: For ( x^2 + 5x + 6 = 0 ), I note down ( a = 1, b = 5, c = 6 ).<\/li>\n\n\n\n- Then, I do mental factorisation<\/strong> \u2014 I split the middle term into two numbers whose product equals ( a \u00d7 c ).
For example, ( x^2 + 5x + 6 = 0 ) \u2192 ( (x + 2)(x + 3) = 0 )
So, the roots are x = -2 and -3<\/strong>.
I apply the same logic for the second equation and get both roots instantly.
<\/li>\n\n\n\n- Next, I compare both roots directly.<\/strong>
<\/strong>\n- \n
- If both x-roots are greater \u2192 ( x > y )<\/li>\n\n\n\n
- If both are smaller \u2192 ( x < y )<\/li>\n\n\n\n
- If one is greater and one smaller, Relationship cannot be established.
<\/li>\n<\/ul>\n<\/li>\n\n\n\n - If the equation looks difficult to factorise<\/strong>, I don\u2019t waste time.
I quickly use the quadratic formula<\/strong> ( x = \\frac{-b \\pm \\sqrt{b^2 – 4ac}}{2a} ) just to get an idea of the approximate roots \u2014 enough to compare and mark the right option.
<\/li>\n\n\n\n- I also use sign patterns<\/strong> to save time:
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- If all signs are positive \u2192 both roots are negative.
<\/li>\n\n\n\n - If the last term is positive and the middle term is negative, both roots are positive.
<\/li>\n\n\n\n - If the last term is negative, the roots are of opposite signs.
<\/li>\n<\/ul>\n<\/li>\n\n\n\n - I simplify equations when needed<\/strong> by dividing all terms by ( a ) if ( a \u2260 1 ). It makes factorisation easier.
<\/li>\n\n\n\n- I practice 10\u201315 quadratic questions daily<\/strong> using a timer (about 30 seconds per question). This helps me stay quick and confident in the exam.<\/li>\n\n\n\n
- I double-check signs<\/strong> instead of recalculating everything \u2014 that avoids silly mistakes.<\/li>\n<\/ul>\n\n\n\n
Final Words<\/h2>\n\n\n\n
The Quadratic Equation topic is a must-master chapter for the SEBI Grade A 2025 Exam. It not only tests your conceptual clarity but also helps you score quickly. By practicing regularly, revising formulas, and solving mock tests, you can easily secure 4\u20135 marks within 3 minutes in this topic.<\/p>\n\n\n\n
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Join our unique Telegram group immediately to skyrocket your preparation for Regulatory exams via expert guidance, top tips, perfect feedback, and much more!<\/em><\/strong><\/p>\n\n\n\n
[ Click Here to join the PracticeMock Telegram Group!<\/a> ]<\/strong><\/p>\n\n\n\n
- I practice 10\u201315 quadratic questions daily<\/strong> using a timer (about 30 seconds per question). This helps me stay quick and confident in the exam.<\/li>\n\n\n\n
- I also use sign patterns<\/strong> to save time:
- Then, I do mental factorisation<\/strong> \u2014 I split the middle term into two numbers whose product equals ( a \u00d7 c ).
- Sign Pattern Recognition:<\/strong>
- Factorisation Method:<\/strong>
- Coefficient of ( x^2 )<\/strong> \u2192 ( a )<\/li>\n\n\n\n
- Standard form<\/strong> \u2192 ( ax^2 + bx + c = 0 )<\/li>\n\n\n\n
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