{"id":160155,"date":"2025-07-11T17:14:03","date_gmt":"2025-07-11T11:44:03","guid":{"rendered":"https:\/\/www.practicemock.com\/blog\/?p=160155"},"modified":"2025-07-11T17:14:04","modified_gmt":"2025-07-11T11:44:04","slug":"alphabet-numbers-series-for-sbi-po","status":"publish","type":"post","link":"https:\/\/www.practicemock.com\/blog\/alphabet-numbers-series-for-sbi-po\/","title":{"rendered":"Alphabet Numbers Series for SBI PO 2025, Know Types of Questions Asked"},"content":{"rendered":"
Home<\/a><\/span> \u00bb SBI PO<\/a><\/span> \u00bb Alphabet Numbers Series for SBI PO 2025<\/span><\/span><\/div>\n\n\n

As the SBI PO 2025 Exam is just around the corner, students have started the last few days’ hustle, and to keep yourself ahead in the competition, you need to prepare hard but smartly. If you are fully prepared and want to revise or want to know some easy tricks to solve the most scoring topic of the reasoning section, that is, alphabet number series, then this blog is for you. <\/p>\n\n\n\n

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Take three free topic tests for SBI PO 2025 Exam<\/a><\/div>\n<\/div>\n\n\n\n

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What is an Alphabet Number Series?<\/strong><\/h2>\n\n\n\n

In this exercise, you will receive a sequence of 1-26 alphabet letters and 0-9 numbers in a specific pattern. Your task is to find the missing letter or number, identify the next term in the series, or spot the odd one out. Each letter is connected to a specific numeric position. <\/p>\n\n\n\n

Example: A=1, B=2\u2026.. and so on.<\/p>\n\n\n\n

Types of Alphabet Number Series Questions asked in SBI PO <\/strong><\/h2>\n\n\n\n

Pure Alphabet Series<\/strong><\/h3>\n\n\n\n

In this type, only alphabets (letters) are used in a fixed pattern. <\/p>\n\n\n\n

Example: <\/strong>A,C,E,G_ ? <\/p>\n\n\n\n

Where the value of A=1, C=3, E=5, G=7, predict the next alphabet. <\/p>\n\n\n\n

Solution: <\/strong>If you have noticed the question, the alphabets given are +2 in pattern, so the next one will be I, whose value is 9. A, C, E, G, I.<\/p>\n\n\n\n

Alphabet + Number Alternating Series<\/strong><\/h3>\n\n\n\n

In this type, alphabets and numbers are arranged in alternating order.<\/p>\n\n\n\n

Example:<\/strong> A, 2, C, 4, E, ?<\/p>\n\n\n\n

Solution:<\/strong> By decoding the value of alphabets, we get A=1, C=3, E=5, and so on. If you observe here, also numbers are in a +2 pattern. So after E, we will get 6. Hence, A, 2, C, 4, E, 6. <\/p>\n\n\n\n

Reverse Alphabet Series<\/strong><\/h3>\n\n\n\n

In this reverse alphabetical order is asked, reverse alphabetical order means {Z=1, Y=2 \u2026\u2026A=26}. <\/p>\n\n\n\n

Example: <\/strong>D = 23, F = 21, H = 19, ?<\/p>\n\n\n\n

Solution: <\/strong>D = 4 normally, but in reverse: Z = 1 \u2192 D = 26 – 4 + 1 = 23, in the same way F = 6 \u2192 26 – 6 + 1 = 21 and H = 8 \u2192 26 – 8 + 1 = 19. If you have observed that the pattern this series follows is numbers are decreasing by 2 (-2). <\/strong>So, next: 19 – 2 = 17 \u2192 Reverse of 17 is J<\/strong><\/p>\n\n\n\n

Alphanumeric Position Logic<\/strong><\/h3>\n\n\n\n

In this type of series, each term is a combination of a number and a letter that follows a fixed arithmetic logic. <\/p>\n\n\n\n

Example: <\/strong>3C, 6F, 9I, ?<\/p>\n\n\n\n

Solution:<\/strong> Numbers are increasing in a pattern of +3, i.e., 3+3=6, 6+3=9. In alphabets, also a +3 pattern is observed. I.e, C=3+3=6, which is F, and so on. The answer is 9+3=12 And in alphabets I(9) + 3 = 12L. So the answer is 12L. <\/p>\n\n\n\n

Vowel\/Consonant-Based Pattern<\/strong><\/h3>\n\n\n\n

In this type of question, vowels and consonants are patterned in alphabetical order. <\/p>\n\n\n\n

Example:<\/strong> A, E, I, O, ?<\/p>\n\n\n\n

Solution:<\/strong> In the question asked above, it contains vowels in order, so the next vowel that comes after O is U. <\/p>\n\n\n\n

Code-Based Alphabet Series<\/strong><\/h3>\n\n\n\n

In this type of question, letters are replaced by numerical values and follow arithmetic operations(+, -)<\/p>\n\n\n\n

Example:<\/strong> C = 3, F = 6, I = 9, ?<\/p>\n\n\n\n

Solution:<\/strong> If you notice the pattern in the above questions, you will find that they follow a +3 pattern. So, as I=9, if you add +3 to 9, it gives 12, and when we put 12 in the alphabetical series, it will come to L. Hence, L=12 is the answer. <\/p>\n\n\n\n

Embedded Position-Based Questions\u00a0<\/strong><\/h3>\n\n\n\n

In this type of question, you have to find the position of an alphabet that is relative to another number. <\/p>\n\n\n\n

Example: <\/strong>Find the letter 3rd to the left of the letter which is 5th from the right end<\/strong> in the word: “ABCDEFGHIJKLMNOPQRSTUVWXYZ”<\/p>\n\n\n\n

Solution: <\/strong>Find the letter 5th from the right end<\/strong> \u2192 From Z backwards:  Z (1st), Y (2nd), X (3rd), W (4th), V (5th)
<\/strong>Now find the 3rd to the left of V<\/strong> \u2192 Move three letters left from V: V \u2192 U (1), T (2), S (3)
The answer is <\/strong>S.<\/p>\n\n\n\n

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