{"id":102001,"date":"2024-07-16T18:07:55","date_gmt":"2024-07-16T12:37:55","guid":{"rendered":"https:\/\/www.practicemock.com\/blog\/?p=102001"},"modified":"2024-07-16T19:17:14","modified_gmt":"2024-07-16T13:47:14","slug":"permutation-and-combination-for-ibps-rrb-exam","status":"publish","type":"post","link":"https:\/\/www.practicemock.com\/blog\/permutation-and-combination-for-ibps-rrb-exam\/","title":{"rendered":"Permutation and Combination For IBPS RRB Exam, Check Tips and Tricks"},"content":{"rendered":"\n

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Home<\/a><\/span> \u00bb Banking & Insurance<\/a><\/span> \u00bb Permutation and Combination For IBPS RRB Exam<\/span><\/span><\/div>\n\n\n

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Permutation and Combination For IBPS RRB Exam: <\/strong>Permutations and combinations are important topics for IBPS RRB exams. Permutations tackle arranging objects in a particular order. The order matters in permutations. Combination, on the other hand, refers to the selection of items without considering the order. The order does not matter in combinations. Combinations focus on selecting objects without considering their order.<\/p>\n\n\n\n

In this blog, we\u2019ll dive into the formulas, tips and tricks, and question samples needed to master Permutation and Combination for IBPS RRB Exam.<\/p>\n\n\n\n

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Permutation and Combination For IBPS RRB Exam, Check Tips and Tricks<\/h2>\n\n\n\n

To make the most of the questions on Permutation and Combination for IBPS RRB Exam, you need to need to understand the basics and the core of it through formulas and examples. Given below are the tips and tricks along with the formulas to tackle this topic.<\/p>\n\n\n\n

Permutations Formula:<\/strong><\/p>\n\n\n\n

The formula for permutations of (n) objects taken (r) at a time is: [ P(n, r) = \\frac{n!}{(n-r)!} ] where (n!) represents the factorial of (n).<\/p>\n\n\n\n

To make it easy, For example, if you have three letters A, B, and C, the different permutations would be ABC, ACB, BAC, BCA, CAB, and CBA.<\/p>\n\n\n\n

Example:<\/strong> If you want to arrange 3 letters out of ABCD, there are (4P3 = 24) ways.<\/p>\n\n\n\n

Combinations Formula:<\/strong><\/p>\n\n\n\n

The formula for combinations of (n) objects taken (r) at a time is: [ C(n, r) = \\frac{n!}{r! \\cdot (n-r)!} ]<\/p>\n\n\n\n

To make it easy, For example, if you have three letters A, B, and C, and you need to select two at a time, the combinations would be AB, AC, and BC.<\/p>\n\n\n\n

Example:<\/strong> If you want to form a committee of 2 males and 3 females from a pool of 8 males and 9 females, there are (C(8, 2) \\cdot C(9, 3) = 2352) ways.<\/p>\n\n\n\n

Permutation and Combination For IBPS RRB Exam, Check Tips and Tricks<\/h2>\n\n\n\n

To master Permutation and Combination for IBPS RRB Exam, you\u2019ll have to read the question properly, look for keywords, master the use of factorials, and solve a different type of problems, know how permutations and combinations relate to probability, and more. Given below is the table that encapsulates the best tips and tricks needed to master the Permutation and Combination for IBPS RRB Exam:<\/p>\n\n\n\n

Permutation and Combination For IBPS RRB Exam, Check Tips and Tricks<\/strong><\/td><\/tr>
Tip\/Trick<\/strong><\/td>Description<\/strong><\/td><\/tr>
Understand the Problem<\/strong><\/td>Read the question carefully to decide or ascertain whether it involves permutations or combinations.<\/td><\/tr>
Identify Keywords<\/strong><\/td>Search for words like \u201carrange,\u201d \u2018\u2019order,\u2019\u2019 \u201cselect,\u201d or \u201cgroup.\u201d<\/td><\/tr>
Practice<\/strong><\/td>Solve a variety of problems to build intuition.<\/td><\/tr>
Use Factorials<\/strong><\/td>Get used to the factorials (e.g., 5!=5\u00d74\u00d73\u00d72\u00d715! = 5 \\times 4 \\times 3 \\times 2 \\times 15!=5\u00d74\u00d73\u00d72\u00d71).<\/td><\/tr>
Visualize<\/strong><\/td>Draw diagrams or visualize scenarios to simplify difficult problems.<\/td><\/tr>
Consonants Together<\/strong><\/td>Treat consonants as a single unit to solve problems like \u201cPERMUTATION\u2019\u2019 while arranging letters.<\/td><\/tr>
Vowels Together<\/strong><\/td>Similarly, treat vowels as a single unit when they need to be together.<\/td><\/tr>
Probability<\/strong><\/td>Understand how permutations and combinations relate to probability.<\/td><\/tr>
Additional Practice<\/strong><\/td>Find permutation and combination questions in previous year papers and watch online videos related to them.<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

Permutation and Combination For IBPS RRB Exam, Best Sample Questions<\/h2>\n\n\n\n

Candidates need to practice as much as they can to master Permutation and Combination for IBPS RRB Exam. Here are the best samples questions that will help you understand the type of questions that might pop up in the IBPS RRB exam:<\/p>\n\n\n\n

Question 1:<\/strong> A group of nine students having at least 6 boys in it is to be selected from a group of 8 boys and 7 girls. Find total number of ways in which the group can be formed.<\/p>\n\n\n\n

A) 1155<\/p>\n\n\n\n

B) 1145<\/p>\n\n\n\n

C) 1125<\/p>\n\n\n\n

D) 1175<\/p>\n\n\n\n

E) None of these<\/p>\n\n\n\n

Question 2:<\/strong> For an exhibition, a group of 7 cars has to be chosen out of 13 cars such that a particular car is always chosen. If the cars have to be chosen one by one, then find the total number of ways of doing so.<\/p>\n\n\n\n

A) 848 \u00d7 6!<\/p>\n\n\n\n

B) 924 \u00d7 7!<\/p>\n\n\n\n

C) 544 \u00d7 7!<\/p>\n\n\n\n

D) 712 \u00d7 6!<\/p>\n\n\n\n

E) None of these<\/p>\n\n\n\n

Question 3:<\/strong> A bag contains 2 blue cubes, 3 green cubes and 4 yellow cubes. In how many ways 3 cubes can be drawn from the bag such that at least one green cube is drawn?<\/p>\n\n\n\n

A) 72<\/p>\n\n\n\n

B) 64<\/p>\n\n\n\n

C) 56<\/p>\n\n\n\n

D) 48<\/p>\n\n\n\n

E) 84<\/p>\n\n\n\n

Question 4:<\/strong> 4 boys or 5 girls are to be selected from a group of 7 boys and 9 girls. Find the total number of ways in which the selection can be made.<\/p>\n\n\n\n

A) 164<\/p>\n\n\n\n

B) 161<\/p>\n\n\n\n

C) 132<\/p>\n\n\n\n

D) 144<\/p>\n\n\n\n

E) None of these<\/p>\n\n\n\n

Question 5:<\/strong> Find the total number of ways in which the word OCCUPATION can be arranged so that all vowels are together.<\/p>\n\n\n\n

A) 48000<\/p>\n\n\n\n

B) 18000<\/p>\n\n\n\n

C) 21600<\/p>\n\n\n\n

D) 72000<\/p>\n\n\n\n

E) None of these<\/p>\n\n\n\n

Question 6:<\/strong> Find the total number of ways of arrangement of the word ACCUMULATION, so that all the vowels are together.<\/p>\n\n\n\n

A) 453600<\/p>\n\n\n\n

B) 682400<\/p>\n\n\n\n

C) 620000<\/p>\n\n\n\n

D) 540500<\/p>\n\n\n\n

E) None of these<\/p>\n\n\n\n

Question 7:<\/strong> In how many ways can the letters of word \u2018BOTTLE\u2019 be arranged?<\/p>\n\n\n\n

A) 1440<\/p>\n\n\n\n

B) 720<\/p>\n\n\n\n

C) 240<\/p>\n\n\n\n

D) 360<\/p>\n\n\n\n

E) None of these<\/p>\n\n\n\n

Question 8:<\/strong> A book shelf has 8 Hindi, 7 English and 11 Sanskrit books. In how many ways can Sourav choose 5 books from the shelf so that it consists of one Hindi, two English and two Sanskrit books?<\/p>\n\n\n\n

A) 8220<\/p>\n\n\n\n

B) 8600<\/p>\n\n\n\n

C) 9240<\/p>\n\n\n\n

D) 9660<\/p>\n\n\n\n

E) None of these<\/p>\n\n\n\n

Question 9:<\/strong> A cricket team of 11 players is to be selected from a group of 8 batsmen, 5 bowlers and 3 wicketkeepers. In how many ways a team having exactly 4 bowlers and 1 wicketkeeper is selected?<\/p>\n\n\n\n

A) 168 ways<\/p>\n\n\n\n

B) 300 ways<\/p>\n\n\n\n

C) 420 ways<\/p>\n\n\n\n

D) 568 ways<\/p>\n\n\n\n

E) None of these<\/p>\n\n\n\n

Question 10:<\/strong> A basketball team of 5 players is to be selected from a group of 7 male players and 6 female players. In how many ways a team having exactly two female players is selected?<\/p>\n\n\n\n

A) 525 ways<\/p>\n\n\n\n

B) 510 ways<\/p>\n\n\n\n

C) 475 ways<\/p>\n\n\n\n

D) 420 ways<\/p>\n\n\n\n

E) None of these<\/p>\n\n\n\n

Solution 1: A)<\/strong><\/p>\n\n\n\n

Desired number of ways = 8<\/sup>C6<\/sub> \u00d7 7<\/sup>C3<\/sub> + 8<\/sup>C7<\/sub> \u00d7 7<\/sup>C2<\/sub> + 8<\/sup>C8<\/sub> \u00d7 7<\/sup>C1<\/sub> = 980 + 168 + 7 = 1155<\/p>\n\n\n\n

Hence, option a.<\/p>\n\n\n\n

Solution 2: B)<\/strong><\/p>\n\n\n\n

Since, 1 car is always chosen, therefore, 6 cars have to be chosen out of 12 cars.<\/p>\n\n\n\n

Therefore, number of ways of choosing the cars = 12<\/sup>C6<\/sub> = 12!\/{6! \u00d7 (12 \u2013 6)!} = 924<\/p>\n\n\n\n

Required number of ways for the exhibition of cars = 924 \u00d7 7!<\/p>\n\n\n\n

Hence, option b.<\/p>\n\n\n\n

Solution 3: B)<\/strong><\/p>\n\n\n\n

The possible cases = (1 green and 2 non green cubes) or (2 green and 1 non green cubes) or (3 green cubes)<\/p>\n\n\n\n

Total number of non green cubes = 2 + 4 = 6<\/p>\n\n\n\n

Also, n<\/sup>Cr<\/sub> = n!\/{n! \u00d7(n \u2013 r)!}<\/p>\n\n\n\n

Therefore, number of ways of selecting 1 green and 2 non-green cubes = 3<\/sup>C1<\/sub> \u00d7 6<\/sup>C2<\/sub> = 3 \u00d7 15 = 45 ways<\/p>\n\n\n\n

Number of ways of selecting 2 green cubes and 1 non-green cube = 3<\/sup>C2<\/sub> \u00d7 6<\/sup>C1<\/sub> = 3 \u00d7 6 = 18 ways<\/p>\n\n\n\n

Number of ways of selecting 3 green cubes = 3<\/sup>C3<\/sub> = 1 way<\/p>\n\n\n\n

Therefore, total number of ways = 45 + 18 + 1 = 64 ways<\/p>\n\n\n\n

Hence, option b.<\/p>\n\n\n\n

Solution 4: B)<\/strong><\/p>\n\n\n\n

Desired number of ways of selection = 7<\/sup>C4<\/sub> + 9<\/sup>C5<\/sub> = 35 + 126 = 161<\/p>\n\n\n\n

Hence, option b.<\/p>\n\n\n\n

Solution 5: C)<\/strong><\/p>\n\n\n\n

Desired number of ways = (6! \u00d7 5!)\/(2! \u00d7 2!) = 21600<\/p>\n\n\n\n

Hence, option c.<\/p>\n\n\n\n

Solution 6: A)<\/strong><\/p>\n\n\n\n

Desired number of ways = (7! \u00d7 6!)\/(2! \u00d7 2! \u00d7 2!) = 453600<\/p>\n\n\n\n

Hence, option a.<\/p>\n\n\n\n

Solution 7: D)<\/strong><\/p>\n\n\n\n

Number of letters in the word BOTTLE = 6<\/p>\n\n\n\n

T appears twice.<\/p>\n\n\n\n

Required number of ways = 6!\/2!<\/p>\n\n\n\n

= 6 \u00d7 5 \u00d7 4 \u00d7 3 = 360<\/p>\n\n\n\n

Hence, option d.<\/p>\n\n\n\n

Solution 8: C)<\/strong><\/p>\n\n\n\n

Number of ways = 8<\/sup>C1<\/sub> \u00d7 7<\/sup>C2<\/sub> \u00d7 11<\/sup>C2<\/sub> = 8 \u00d7 21 \u00d7 55 = 9240<\/p>\n\n\n\n

Hence, option c.<\/p>\n\n\n\n

Solution 9: C)<\/strong><\/p>\n\n\n\n

So, the required number of ways = 3<\/sup>C1<\/sub> \u00d7 5<\/sup>C4<\/sub> \u00d7 8<\/sup>C6<\/sub> = 3 \u00d7 5 \u00d7 28 = 420 ways<\/p>\n\n\n\n

Hence, option c.<\/p>\n\n\n\n

Solution 10: A)<\/strong><\/p>\n\n\n\n

Number of ways of selecting the team = 7<\/sup>C3<\/sub> \u00d7 6<\/sup>C2<\/sub> = 35 \u00d7 15 = 525 ways<\/p>\n\n\n\n

Hence, option a.<\/p>\n\n\n\n

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IBPS RRB Clerk Cut Off 2024<\/a><\/td>IBPS RRB Clerk Previous Year Question Paper<\/a><\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

<\/p>\n\n\n\n

Permutation and Combination For IBPS RRB Exam FAQs<\/h2>\n\n\n\n
What is the difference between permutations and combinations?<\/strong>

Permutations consider order, while combinations do not.<\/p> <\/div>

Why is it important to read the question carefully in permutation and combination problems?<\/strong>

To decide whether the problem involves permutations or combinations.<\/p> <\/div>

What are some best tips and tricks to master permutation and combination problems for the IBPS RRB exam?<\/strong>

Understand the problem, identify keywords, and practice a variety of problems.<\/p> <\/div> <\/div>\n","protected":false},"excerpt":{"rendered":"

Discover the step-by-step process for solving questions on Permutation and Combination For IBPS RRB Exam. Get important tips and tricks<\/p>\n","protected":false},"author":6,"featured_media":102009,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_uag_custom_page_level_css":"","_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_uf_show_specific_survey":0,"_uf_disable_surveys":false,"footnotes":""},"categories":[22],"tags":[],"class_list":["post-102001","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-banking-insurance"],"yoast_head":"\nPermutation and Combination For IBPS RRB Exam, Check Tips and Tricks<\/title>\n<meta name=\"description\" content=\"Discover the step-by-step process for solving questions on Permutation and Combination For IBPS RRB Exam. 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