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High level DI for SBI PO: The preparation for data interpretation for SBI PO exam is a must, especially from the perspective of mains. A separate section is dedicated just for DI in SBI PO mains. If you have been looking for high level DI for SBI PO questions, then you have arrived at the right place. You will get exposed to different type of DI-based questions today. With answer key it will also help you in arriving at the right conclusion in terms of your approach. Analyse your approach based on the answer key.

## Caselet DI:

4000 people (male + female) participated in an event and categorised in three different categories i.e. VVIP, VIP and normal people. Ratio of VIPs to VVIPs who participated in the event is 7:5. Out of total normal people who participated in the event, 40% were males which were 512 less than number of male VIPs who participated in the event. Out of total VVIPs who participated in the event, 450 were males, while the sum of number of female VIPs and VVIPs together who participated in the event was 1470.

Common Solution:

Let the number of VIPs and VVIPs who participated in the event be 7x and 5x, respectively

Therefore, number of normal people who participated in the event = 4000 – (7x + 5x) = (4000 – 12x)

Number of normal males who participated in the event = 0.4(4000 – 12x) = (1600 – 4.8x)

Number of normal females who participated in the event = 0.6(4000 – 12x) = (2400 – 7.2x)

Number of male VIPs who participated in the event = 1600 – 4.8x + 512 = (2112 – 4.8x)

Number of female VIPs who participated in the event = 7x – (2112 – 4.8x) = (11.8x – 2112)

Number of male VVIPs who participated in the event = 450

Number of female VVIPs who participated in the event = (5x – 450)

According to the question,

11.8x – 2112 + 5x – 450 = 1470

Or, 16.8x = 4032

Or, x = 240

Therefore, number of normal people who participated in the event = (4000 – 12x) = 1120

Number of normal males who participated in the event = 0.4 ×1120 = 448

Number of normal females who participated in the event = 1120 – 448 = 672

Number of VIPs who participated in the event = 7x = 1680

Number of male VIPs who participated in the event = 448 + 512 = 960

Number of female VIPs who participated in the event = 1680 – 960 = 720

Number of VVIPs who participated in the event = 5x = 1200

Number of male VVIPs who participated in the event = 450

Number of female VVIPs who participated in the event = 1200 – 450 = 750

1.) Find the sum of the number of normal females and female VIPs who participated in the event.

a.) 1382

b.) 1424

c.) 1248

d.) 1392

e.) 1164

Answer: d)

Solution:

Required sum = 672 + 720 = 1392

Hence, option d.

## Mixed Chart DI:

The given pie-chart shows the percentage distribution of total number of five different types of energy drinks sold on Monday and Friday together. The number of bottles of Amp sold on Monday and Friday together is 360 more than the number of bottles of Nos sold on Monday and Friday together.

The given line graph shows the percentage of number of bottles of each energy drink sold on Monday out of the total number of bottles of that drink sold on Monday and Friday together.

Common Solution:

Let the total number of bottles of given five energy drinks sold on Monday and Friday together be ‘x’

Therefore, number of bottles of Nos sold on Monday and Friday together = 0.18x

Number of bottles of Amp sold on Monday and Friday together = 0.26x

According to the question,

0.26x – 0.18x = 360

Or, 0.08x = 360

Or, x = 360/0.08 = 4500

Therefore,

Number of bottles of Red bull sold on Monday and Friday together = 0.12x = 540

Number of bottles of Red bull sold on Monday = 0.25 × 540 = 135

Number of bottles of Red bull sold on Friday = 540 – 135 = 405

Similarly,

1.) Number of bottles of Bang sold on Friday is how much percent more/less than the number of bottles of Monster sold on Monday?

a.) 12%

b.) 30%

c.) 15%

d.) 20%

e.) 25%

Answer: d)

Solution:

Required percentage = {(432 – 360)/360} × 100 = 20%

Hence, option d.

## High level DI for SBI PO – Missing DI

The table given below shows the number of smart bulbs manufactured by five different companies in 2017. It also shows the percentage of these smart bulbs sold, price of each bulb and total revenue generated by the sale of these bulbs by each company.

Common Solution:

1.) What is the difference between the total revenue generated by Bajaj and that by Surya by selling smart bulbs in 2017?

a.) Rs. 15,120

b.) Rs. 11,300

c.) Rs. 14,520

d.) Rs. 15,280

e.) Rs. 12,340

Answer: c)

Solution:

Desired difference = 48000 – 33480 = Rs. 14,520

Hence, option c.

## Pie Chart DI

The pie chart given below shows the percentage distribution of the number of B-schools which got different ratings i.e. (5, 4, 3, 2 and 1) out of 5 in terms of placement criteria. The average number of professors in each B-school with grade 2 is 17, while the total number of professors in all the B-schools with grade 2 is 3468.

Common Solution:

Number of B-schools which received grade 2 = 3468/17 = 204

Total number of B-schools together = (204/17) × 100 = 1200

Topic: Pie chart

Sub topic: Normal

Lvl: 1

Q1. Average number of students per B-school with grade 4 is 84. If the ratio of the total number of boys to girls in all the B-schools with grade 4 is 11: 9, then find the total number of girls in all the B-schools together with grade 4.

a) 6804

b) 7210

c) 6640

d) 6274

e) None of these

Ans: a

Solution:

Total number of students = 180 × 84 = 15120

Required number of girls = 9/20 × 15120 = 6804

Hence, option a.

## Arithmetic Based DI

The line graph given below shows the percentage by which five different friends marked their goods above the cost price, and the discount percentage given and the amount (in Rs.) for which they sold their articles.

Common Solution:

For Carryminati:

Let cost price of the article = Rs. 100x

Marked price of the article = 1.6 × 100x = Rs. 160x

Selling price of the article = 0.6 × 160x = 96x

So, 96x = 768

x = 8

Cost price of the article = Rs. 800

Marked price of the article = 160 × 8 = Rs. 1280

For Bhuvan:

Let cost price of the article = Rs. 100x

Marked price of the article = 1.5 × 100x = Rs. 150x

Selling price of the article = 0.64 × 150x = 96x

So, 96x = 864

x = 9

Cost price of the article = Rs. 900

Marked price of the article = 150 × 9 = Rs. 1350

For Amit:

Let cost price of the article = Rs. 100x

Marked price of the article = 1.75 × 100x = Rs. 175x

Selling price of the article = 0.72 × 175x = 126x

So, 126x = 756

x = 6

Cost price of the article = Rs. 600

Marked price of the article = 175 × 6 = Rs. 1050

For Ashish:

Let cost price of the article = Rs. 100x

Marked price of the article = 1.65 × 100x = Rs. 165x

Selling price of the article = 0.68 × 165x = 112.2x

So, 112.2x = 1122

x = 10

Cost price of the article = Rs. 1000

Marked price of the article = 165 × 10 = Rs. 1650

For Harsh:

Let cost price of the article = Rs. 100x

Marked price of the article = 1.8 × 100x = Rs. 180x

Selling price of the article = 0.72 × 180x = 129.6x

So, 129.6x = 648

x = 5

Cost price of the article = Rs. 500

Marked price of the article = 180 × 5 = Rs. 900

1. What is the cost price of article for Carryminati?

a.) Rs. 600

b.) Rs. 800

c.) Rs. 850

d.) Rs. 900

e.) None of these

Ans: b

Solution:

Cost price of article for Carryminati = Rs. 800

Hence, option b.

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