Mensuration Questions for SSC CHSL, Download Free PDF

Planning for the SSC CHSL Tier 1 exam? You know the Quantitative Aptitude section is where you can secure easy, high-scoring marks, and Mensuration is important. You can expect at least 2 to 3 direct, formula-based questions from Mensuration in the CHSL exam. I have personally analyzed many previous year question papers and found that mensuration questions are pure formula checks. If you know the formula for the volume of a sphere or the area of a trapezoid, you can solve them easily. In this blog, we’ve provided exam-level Mensuration questions for the SSC CHSL exam in a PDF that you can download for free. But before you download it, take a few free Mensuration tests to analyze your understanding of this topic.

Concept of Mensuration for SSC CHSL

Mensuration is simply the branch of geometry that deals with the measurement of length, area, and volume of different shapes. For the SSC CHSL exam, the topic is divided into two main parts:

1. 2D Mensuration (Area and Perimeter): Deals with flat shapes like squares, rectangles, triangles, circles, and parallelograms.
2. 3D Mensuration (Volume and Surface Area): Deals with solid objects like cubes, cuboids, cylinders, cones, and spheres.

Formulas of Mensuration For 2D Shapes:

Rectangle:

• Area of Rectangle = Length × Breadth.
• Perimeter of a Rectangle = 2 × (Length + Breadth)
• Length of the Diagonal = √(Length² + Breadth²)

Square:

• Area of a Square = Length × Length = (Length)²
• Perimeter of a square = 4 × Length
• Length of the Diagonal = √2 × Length

Parallelogram:

• Area of a Parallelogram = Length × Height
• Perimeter of a Parallelogram = 2 × (Length + Breadth)

Triangle:

• Area of a triangle=(1/2)(Base × Height)

For a triangle with sides measuring a, b and c, respectively:

• Perimeter = a + b + c
• s = semi perimeter = perimeter/2 =  (a+b+c)/2
• Area of Triangle,

Trapezium:

• Area of a trapezium = (1/2) × (sum of parallel sides) × (distance between parallel sides)
  = (1/2) × (AB+DC) × AE
• Perimeter of a Trapezium = Sum of All Sides

Rhombus:

• Area of a rhombus=(1/2)×Product of diagonals
• Perimeter of a rhombus = 4 × l

Mensuration Formulas For 3D Shapes

Shape	Volume (Cubic units)	Curved Surface Area (CSA) or Lateral Surface Area (LSA) (Square units)	Total Surface Area (TSA) (Square units)
Cube	a3	LSA = 4 a2	6 a2
Cuboid	l × b × h	LSA = 2h (l + b)	2 (lb +bh +hl)
Sphere	(4/3) π r3	4 π r2	4 π r2
Hemisphere	(⅔) π r3	2 π r2	3 π r2
Cylinder	π r2 h	2π r h	2πrh + 2πr2
Cone	(⅓) π r2 h	π r l	πr (r + l)

Mensuration Questions for SSC CHSL PDF, Download for Free

The questions SSC asks in the Mensuration section are typically direct-substitution problems. They require quick recall of the formula and accurate calculation. They are the perfect type of question that can save you time for other time-consuming sections. To help you master these quick facts, we have provided a PDF containing the most important and frequently asked Mensuration questions for the exam. Click on the button given below to download the Mensuration Questions for SSC CHSL PDF for free.

Click to Download Mensuration Questions for SSC CHSL PDF

Question 1: Ratio of length to breadth of a rectangular field is 8:5 and its area is 324 m² less than area of a squared field whose perimeter is 168 meters. Find the perimeter of the rectangular field.

A) 164 m

B) 142 m

C) 156 m

D) 148 m

Question 2: A copper wire is bent in the form of square whose area is 484 cm². It the same wire is bent in the form of a circle, find the area of the circle.

A) 524 cm²

B) 616 cm²

C) 924 cm²

D) 800 cm²

Question 3: If each side of a square is increased by 20%, what will be the percentage increase in its original area?

A) 30%

B) 37%

C) 44%

D) 47%

Question 4: How many metres of a cloth of width 15 metre is required to make a conical tent of height 72 metre and base radius 21 cm.

A) 290

B) 450

C) 330

D) 420

Question 5: The total surface area of a solid cube is 3456 cm². Find the volume (in cm³) of the cube.

A) 13824

B) 12824

C) 13884

D) 12864

Question 6: If the ratio of volumes of two cones is 64:125 and the ratio of their heights is 8:5, then the ratio of their base areas will be:

A) 32:7

B) 25:8

C) 5:2

D) 15:4

Question 7: A solid spherical iron ball having radius 12 cm is melted to form smaller balls of radius 8 mm each. Find the number of such spherical iron balls obtained.

A) 3375

B) 2415

C) 3240

D) 2875

Question 8: Find the length of the longest rod that can be put in a 12 m long, 8 metres broad and 20 metres high room.

A) 5√12 metres

B) 4√38 metres

C) 3√34 metres

D) 5√33 metres

Question 9: The internal and external angles of a regular polygon are in the ratio 2:1, Find the sum of the internal angles.

A) 640^o

B) 720^o

C) 480^o

D) 560^o

Question 10: : A solid copper sphere of radius 9 cm is melted and moulded into a right circular cylindrical rod of radius 3 cm. What is the length of this rod?

A) 112 cm

B) 108 cm

C) 180 cm

D) 90 cm

Click to Download Mensuration Questions for SSC CHSL PDF

Preparation Tips for SSC CHSL Mensuration Questions

Mensuration is an easy score-maker if you follow a dedicated strategy. These tips will help you maximize your problem-solving skills for this topic:

1. Create a Formula Chart: Dedicate one single page to write down every single 2D and 3D formula. Revise this chart every day for instant recall.
2. Use Pythagoras Triples: Memorize common Pythagorean triplets (e.g., 3-4-5, 5-12-13, 8-15-17). These are often used to find missing dimensions (height, diagonal) quickly without complex calculations.
3. Practice Conversion: Be careful with units! Practice converting between meters and centimeters, and between area (cm²) and volume (cm³).
4. Know the Ratio Rules: Memorize rules like: if the side ratio is a:b, the area ratio is a²:b², and the volume ratio is a³:b³. This saves huge calculation time.
5. Solve High Volume: Mensuration requires high repetition. Solve a dedicated set of 25 questions daily using our free topic tests to solidify your formula application.

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