The IBPS RRB PO Expected 40 Quant Questions 2026 cover important topics such as Data Interpretation, Arithmetic, Simplification, Approximation, Number Series and Quadratic Equations. The IBPS RRB PO Prelims Quantitative Aptitude section carries 40 questions for 40 marks, with a sectional time limit of 20 minutes. This practice set includes 40 expected questions with answers and step-by-step explanations based on previous-year question trends. Practice these questions to improve calculation speed, accuracy and time management for the IBPS RRB PO 2026 examination.
The following 40 IBPS RRB PO Quant Questions follow a mixed-topic practice pattern based on recurring question types. The distribution below is a practice-set structure, not an officially prescribed topic-wise weightage.
| Topic | Number of Questions |
| Approximation | 5 |
| Missing Number Series | 5 |
| Quadratic Equations | 5 |
| Data Interpretation | 15 |
| Arithmetic | 10 |
| Total | 40 |
For more preparation guidance, read IBPS RRB PO Topic Wise Weightage 2026.
Directions: Find the approximate value that should replace the question mark (?) in each question.
Q1. ? = 39.98% of 549.99 + 24.99% of 799.98
Answer: 420
Solution:
= 40% of 550 + 25% of 800
= 220 + 200
= 420
Q2. 12.012 × 14.992 + 624.99 = ?
Answer: 805
Solution:
= 12 × 15 + 625
= 180 + 625
= 805
Q3. ? × 4.99 = 119.98% of 749.91 − 250.02
Answer: 130
Solution:
? × 5 = 120% of 750 − 250
? × 5 = 900 − 250
? × 5 = 650
? = 650 ÷ 5 = 130
Q4. 79.99 × 4.01 + 143.98 ÷ 2 = ?
Answer: 392
Solution:
= 80 × 4 + 144 ÷ 2
= 320 + 72
= 392
Q5. 349.98 ÷ 6.99 + 249.99 ÷ 4.99 = ?
Answer: 100
Solution:
= 350 ÷ 7 + 250 ÷ 5
= 50 + 50
= 100
Candidates should understand the IBPS RRB PO exam pattern and syllabus to become familiar with the question distribution, important topics and examination structure.
Directions: Find the missing number (?) in each of the following series.
Q6. 8, 11, 17, 29, 53, ?
Answer: 101
Solution:
The differences are:
+3, +6, +12, +24
The differences are multiplied by 2 each time.
Next difference = 24 × 2 = 48
Missing number = 53 + 48 = 101
Q7. 12, 13, 28, 87, 352, ?
Answer: 1765
Solution:
The pattern is:
12 × 1 + 1 = 13
13 × 2 + 2 = 28
28 × 3 + 3 = 87
87 × 4 + 4 = 352
Next number = 352 × 5 + 5 = 1765
Q8. 150, 148, 143, 133, 116, ?
Answer: 90
Solution:
The differences are:
−2, −5, −10, −17
The differences between these values are −3, −5, −7.
Next difference = −9
Therefore, the next term is:
116 − 26 = 90
Q9. 24, 12, 12, 18, 36, ?
Answer: 90
Solution:
The pattern is:
24 ÷ 2 = 12
12 × 1 = 12
12 × 1.5 = 18
18 × 2 = 36
36 × 2.5 = 90
Q10. 4, 9, 25, 49, 121, ?
Answer: 169
Solution:
All the numbers are squares of consecutive prime numbers.
2² = 4
3² = 9
5² = 25
7² = 49
11² = 121
Next prime number = 13
13² = 169
Attempting regular IBPS RRB PO mock tests can help candidates evaluate their performance, identify weak areas and improve time management before the examination.
Directions: In each question, two equations (I) and (II) are given. Solve both equations and establish the relationship between x and y.
Use the following options:
Q11.
I. x² − 11x + 30 = 0
II. y² − 13y + 42 = 0
Answer: (D) x ≤ y
Solution:
Equation I:
x² − 11x + 30 = 0
(x − 5)(x − 6) = 0
x = 5, 6
Equation II:
y² − 13y + 42 = 0
(y − 6)(y − 7) = 0
y = 6, 7
Both possible values of x are less than or equal to the corresponding minimum value of y.
Therefore, x ≤ y.
Q12.
I. 2x² + 7x + 6 = 0
II. y² + 5y + 6 = 0
Answer: (C) x ≥ y
Solution:
Equation I:
(2x + 3)(x + 2) = 0
x = −3/2, −2
Equation II:
(y + 2)(y + 3) = 0
y = −2, −3
The smallest value of x is −2, and the greatest value of y is −2.
Therefore, x ≥ y.
Q13.
I. x² = 64
II. y = 64
Answer: (B) x < y
Solution:
From equation I:
x² = 64
x = ±8
From equation II:
y = 64
Both possible values of x (−8 and 8) are less than 64.
Therefore, x < y.
Q14.
I. x² − 5x − 24 = 0
II. y² − 7y − 18 = 0
Answer: (B) x < y
Solution:
Equation I:
(x − 8)(x + 3) = 0
x = 8, −3
Equation II:
(y − 9)(y + 2) = 0
y = 9, −2
Both possible values of x are less than the corresponding values of y.
Therefore, x < y.
Q15.
I. 3x² − 10x + 8 = 0
II. 2y² − 7y + 6 = 0
Answer: (E) Relationship cannot be established
Solution:
Equation I:
3x² − 10x + 8 = 0
(3x − 4)(x − 2) = 0
x = 4/3, 2
Equation II:
2y² − 7y + 6 = 0
(2y − 3)(y − 2) = 0
y = 3/2, 2
The possible values overlap, and neither variable is consistently greater than or equal to the other.
Therefore, the relationship cannot be established.
Data Interpretation is an important part of the IBPS RRB PO Quantitative Aptitude section. The following three sets cover table-based DI, bar graph DI and caselet DI, testing calculations involving averages, percentages, ratios and differences.
Directions: The table below shows the total number of books sold by three different shops (A, B and C) over three months.
| Month | Shop A | Shop B | Shop C |
| January | 120 | 150 | 180 |
| February | 160 | 140 | 210 |
| March | 200 | 180 | 160 |
Q16. What is the average number of books sold by Shop B across all three months?
Answer: 156.67
Solution:
Total books sold by Shop B:
= 150 + 140 + 180 = 470
Average = 470 ÷ 3 = 156.67
Q17. The number of books sold by Shop A in March is what percentage more or less than the books sold by Shop C in January?
Answer: 11.11% more
Solution:
Difference = 200 − 180 = 20
Percentage increase = (20 ÷ 180) × 100
= 11.11% more
Q18. Find the ratio of the total books sold by Shop A and Shop B together in February to the total books sold by Shop C in February and March together.
Answer: 30:37
Solution:
Shop A and B in February:
= 160 + 140 = 300
Shop C in February and March:
= 210 + 160 = 370
Required ratio = 300:370
= 30:37
Q19. If Shop A sells each book for ₹250 in January, what is the total revenue generated by Shop A in that month?
Answer: ₹30,000
Solution:
Total books sold = 120
Revenue = 120 × ₹250
= ₹30,000
Q20. Total books sold by all three shops in March is how much more or less than the total books sold by all three shops in January?
Answer: 90 more
Solution:
Total books sold in March:
= 200 + 180 + 160 = 540
Total books sold in January:
= 120 + 150 + 180 = 450
Difference = 540 − 450
= 90 more
Directions: The following data shows the number of male and female employees working in five different departments of a company.
| Department | Male Employees | Female Employees | Total Employees |
| IT | 45 | 35 | 80 |
| HR | 20 | 40 | 60 |
| Sales | 50 | 30 | 80 |
| Finance | 30 | 25 | 55 |
| Admin | 15 | 20 | 35 |
| Total | 160 | 150 | 310 |
Q21. What is the total number of female employees working across all five departments?
Answer: 150
Solution:
Total female employees:
= 35 + 40 + 30 + 25 + 20
= 150
Q22. The number of male employees in the Sales department is what percentage of the total employees in the IT department?
Answer: 62.5%
Solution:
Total IT employees = 45 + 35 = 80
Male employees in Sales = 50
Required percentage:
= (50 ÷ 80) × 100
= 62.5%
Q23. Find the ratio of total employees (male + female) in the HR department to the total employees in the Finance department.
Answer: 12:11
Solution:
HR employees = 20 + 40 = 60
Finance employees = 30 + 25 = 55
Required ratio = 60:55
= 12:11
Q24. If 20% of the male employees from the IT department transfer to the Admin department, what will be the new number of male employees in Admin?
Answer: 24
Solution:
Male employees transferred from IT:
= 20% of 45
= 9
Existing male employees in Admin = 15
New number = 15 + 9
= 24
Q25. Find the difference between the total number of male employees and total female employees in the company.
Answer: 10
Solution:
Total male employees:
= 45 + 20 + 50 + 30 + 15
= 160
Total female employees = 150
Difference = 160 − 150
= 10
Directions: Read the following information carefully and answer the questions.
In a college, there are 400 students who like three different sports: Cricket, Football and Hockey.
Q26. How many students like both Cricket and Hockey but not Football?
Answer: 50
Solution:
Only Cricket = 20% of 400 = 80
Only Football = 15% of 400 = 60
Only Hockey = 25% of 400 = 100
All three sports = 10% of 400 = 40
Students liking both Cricket and Hockey:
= 400 − (80 + 60 + 100 + 40 + 40 + 30)
= 50
Q27. What is the total number of students who like Cricket?
Answer: 210
Solution:
Total students who like Cricket:
= Only Cricket + Cricket and Football + Cricket and Hockey + All three
= 80 + 40 + 50 + 40
= 210
Q28. Find the ratio of students who like only Football to those who like only Hockey.
Answer: 3:5
Solution:
Only Football = 60
Only Hockey = 100
Required ratio = 60:100
= 3:5
Q29. The number of students who like exactly two sports is what percentage of the total students?
Answer: 30%
Solution:
Students liking exactly two sports:
= 40 + 30 + 50
= 120
Required percentage:
= (120 ÷ 400) × 100
= 30%
Q30. How many students do not like Football?
Answer: 230
Solution:
Students who do not like Football:
= Only Cricket + Only Hockey + Cricket and Hockey but not Football
= 80 + 100 + 50
= 230
Arithmetic questions test candidates’ understanding of basic mathematical concepts and their ability to solve word problems quickly. The following questions cover important topics such as Ages, Partnership, Profit and Loss, Interest, Time and Work, Speed and Distance, Mixture and Alligation, Mensuration and Probability.
Q31. Ages
The ratio of the current ages of A and B is 4:5. After 5 years, the ratio of their ages will become 5:6. Find the present age of A.
Answer: 20 years
Solution:
Let the present ages of A and B be 4x and 5x.
According to the question:
(4x + 5) / (5x + 5) = 5/6
6(4x + 5) = 5(5x + 5)
24x + 30 = 25x + 25
x = 5
Present age of A = 4 × 5
= 20 years
Q32. Partnership
A and B start a business by investing ₹12,000 and ₹16,000, respectively. After 8 months, C joins them with an investment of ₹20,000. If the total annual profit is ₹46,000, find C’s share of the profit.
Answer: ₹8,846.15 (approximately)
Solution:
Profit-sharing ratio:
A = 12,000 × 12 = 1,44,000
B = 16,000 × 12 = 1,92,000
C = 20,000 × 4 = 80,000
Ratio = 144:192:80
= 9:12:5
Total parts = 9 + 12 + 5 = 26
C’s share:
= (5 ÷ 26) × 46,000
= ₹8,846.15 approximately
Q33. Profit and Loss
A shopkeeper marks up his goods by 40% above the cost price and then allows a discount of 20% on the marked price. Find his overall profit or loss percentage.
Answer: 12% profit
Solution:
Let the cost price = ₹100
Marked price = 100 + 40 = ₹140
Selling price = 140 − 20% of 140
= 140 − 28 = ₹112
Profit = 112 − 100 = ₹12
Profit percentage = 12%
Q34. Simple and Compound Interest
A sum of ₹8,000 is invested at 10% per annum compound interest, compounded annually for 2 years. Find the total interest earned.
Answer: ₹1,680
Solution:
Principal = ₹8,000
Rate = 10%
Time = 2 years
Amount = 8,000 × (1 + 10/100)²
= 8,000 × 1.21
= ₹9,680
Compound Interest = 9,680 − 8,000
= ₹1,680
Q35. Time and Work
A can complete a piece of work in 12 days, and B can complete the same work in 18 days. If they work together for 4 days, what fraction of the work is left?
Answer: 4/9
Solution:
A’s one-day work = 1/12
B’s one-day work = 1/18
Combined one-day work:
= 1/12 + 1/18
= 5/36
Work completed in 4 days:
= 5/36 × 4
= 20/36 = 5/9
Remaining work:
= 1 − 5/9
= 4/9
Q36. Time, Speed and Distance
A train running at a speed of 72 km/h crosses a pole in 15 seconds. Find the length of the train in metres.
Answer: 300 metres
Solution:
Speed = 72 × 5/18
= 20 m/s
Length of train = Speed × Time
= 20 × 15
= 300 metres
Q37. Boats and Streams
A boat can travel at a speed of 12 km/h in still water. If the speed of the stream is 3 km/h, find the time taken by the boat to travel 45 km downstream.
Answer: 3 hours
Solution:
Downstream speed = Speed in still water + Stream speed
= 12 + 3 = 15 km/h
Time = Distance ÷ Speed
= 45 ÷ 15
= 3 hours
Q38. Mixture and Alligation
A 60-litre mixture contains milk and water in the ratio 7:3. How many litres of water must be added to make the ratio of milk to water 1:1?
Answer: 24 litres
Solution:
Total mixture = 60 litres
Milk = 60 × 7/10 = 42 litres
Water = 60 × 3/10 = 18 litres
For a 1:1 ratio, water must equal milk.
Additional water required:
= 42 − 18
= 24 litres
Q39. Mensuration
The length of a rectangle is 4 cm more than its breadth. If the perimeter of the rectangle is 48 cm, find its area.
Answer: 140 cm²
Solution:
Let breadth = x cm
Length = (x + 4) cm
Perimeter = 2 × (Length + Breadth)
48 = 2(x + 4 + x)
24 = 2x + 4
2x = 20
x = 10 cm
Breadth = 10 cm
Length = 14 cm
Area = Length × Breadth
= 14 × 10
= 140 cm²
Q40. Permutation and Probability
A bag contains 4 red, 5 blue and 3 green balls. If two balls are drawn at random, what is the probability that both balls are blue?
Answer: 5/33
Solution:
Total balls = 4 + 5 + 3 = 12
Blue balls = 5
Probability of drawing the first blue ball = 5/12
Probability of drawing the second blue ball = 4/11
Required probability:
= (5/12) × (4/11)
= 20/132
= 5/33
Candidates should focus on accuracy and calculation speed while practising these IBPS RRB PO Prelims Quant Questions. Since the section has 40 questions to be attempted in 20 minutes, spending too much time on one difficult question can affect the overall score.
Follow these preparation tips:
The IBPS RRB PO Expected 40 Quant Questions provide practice across important topics based on previous-year examination trends. Candidates should solve these questions within a 20-minute time limit to develop speed and accuracy. Regular revision, sectional practice and mock test analysis can help improve performance. Visit PracticeMock for more banking exam preparation resources and mock tests.
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The IBPS RRB PO Prelims examination contains 40 Quantitative Aptitude questions carrying 40 marks. Candidates get 20 minutes to complete this section, so calculation speed and effective time management are important.
Important topics include Data Interpretation, Simplification, Approximation, Number Series, Quadratic Equations, Percentage, Profit and Loss, Ratio, Average, Time and Work, and Time, Speed and Distance.
The difficulty level generally ranges from easy to moderate, although some shifts may include lengthy calculations and challenging DI sets. Candidates should practise different question types to improve their ability to handle varying difficulty levels.
Based on previous-year trends, Data Interpretation can account for approximately 10–15 questions. The actual number and types of DI sets may vary across examination shifts.
Yes. IBPS deducts 0.25 marks for every incorrect answer. Candidates should focus on accuracy and avoid attempting questions through random guessing.
Candidates get 20 minutes to solve all 40 Quantitative Aptitude questions. Practising with a timer can help improve calculation speed and question selection.
Yes. Quadratic Equations have appeared regularly in previous IBPS RRB PO Prelims papers. Candidates should practise factorisation, finding roots and comparing the values of x and y.
Practise multiplication tables, squares, cubes, percentage-to-fraction conversions and approximation techniques. Regular timed practice and mock test analysis can also improve calculation speed and accuracy.
These 40 questions provide useful topic-wise practice, but they should not be your only preparation resource. Candidates should also solve previous-year papers, practise additional questions and attempt full-length mock tests.
Start with familiar and less time-consuming questions, then move to DI and arithmetic problems. Avoid lengthy calculations initially and maintain a balance between speed and accuracy throughout the 20-minute sectional duration.
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